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A member consists of three sections. The first part is a pipe with an outside diameter of 60 mm and is 0.6 m long. The second section is a solid bar with a length of 200 mm and a diameter of 80 mm. The third section is a 90 mm square bar with a length of 0.5 m. All these sections are of the same material and E = 200 GPa. A tensile load of 180 kN is applied in the member and causes a total strain of 7,628 x 10⁻⁴. Calculate the inside diameter of the pipe, the total change in length, and the total strain energy in the member.

Physics

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Question 1

Given:
Tensile load P=30 kN=30×103 NP = 30 \text{ kN} = 30 \times 10^3 \text{ N}
Modulus of Elasticity E=210 GPa=210×109 PaE = 210 \text{ GPa} = 210 \times 10^9 \text{ Pa}

Section 1 (larger diameter):
Diameter D=50 mm=0.050 mD = 50 \text{ mm} = 0.050 \text{ m}
Length L1=60 mm=0.060 mL_1 = 60 \text{ mm} = 0.060 \text{ m}
Area $A_1 = \frac{\pi D^2}{4} = \frac{\pi (0.

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