This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here are the solutions to the problems: Problem 1: Given: Initial velocity, u = 0 \, ms^-1 (starts from rest) Acceleration, a = 0.5 \, ms^-2 Distance, s = 25 \, m Step 1: Identify the appropriate kinematic equation. Since we have u, a, s and need to find t, we use the equation: s = ut + (1)/(2)at^2 Step 2: Substitute the given values into the equation. 25 = (0)t + (1)/(2)(0.5)t^2 25 = 0.25t^2 Step 3: Solve for t. t^2 = (25)/(0.25) t^2 = 100 t = sqrt(100) t = 10.0 \, s The time taken is 10.0 s. Problem 2: Given: Initial velocity, u = 108 \, kmh^-1 Final velocity, v = 18 \, kmh^-1 Retardation (negative acceleration), a = -5 \, ms^-2 Step 1: Convert velocities from kmh^-1 to ms^-1. To convert kmh^-1 to ms^-1, multiply by (1000)/(3600) or (5)/(18). u = 108 \, kmh^-1 = 108 × (5)/(18) \, ms^-1 = 6 × 5 \, ms^-1 = 30 \, ms^-1 v = 18 \, kmh^-1 = 18 × (5)/(18) \, ms^-1 = 5 \, ms^-1 i) How long will it take to reach 18 \, kmh^-1? Step 2: Use the kinematic equation v = u + at to find time t. 5 = 30 + (-5)t Step 3: Solve for t. 5 - 30 = -5t -25 = -5t t = (-25)/(-5) t = 5.0 \, s The time taken is 5.0 s. Note: The provided answer in the image is 6.0s, but based on the calculation with the given values, the result is 5.0s. ii) What is the distance covered? Step 4: Use the kinematic equation v^2 = u^2 + 2as to find distance s. (5)^2 = (30)^2 + 2(-5)s 25 = 900 - 10s Step 5: Solve for s. 10s = 900 - 25 10s = 875 s = (875)/(10) s = 87.5 \, m The distance covered is 87.5 m. Send me the next one 📸