This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

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D) one fourth as large as that on moon one
To solve this problem, we will use Newton's Law of Universal Gravitation.
Given: • Mass of the planet = • Mass of moon one = • Mass of moon two = (since they have equal mass) • Radius of orbit for moon one = • Radius of orbit for moon two =
The formula for the gravitational force between two objects with masses and separated by a distance is: where is the gravitational constant.
Step 1: Calculate the gravitational force on moon one (). For moon one, the masses are and , and the distance is .
Step 2: Calculate the gravitational force on moon two (). For moon two, the masses are and , and the distance is .
Step 3: Compare with . We can rewrite by factoring out : Since , we can substitute into the equation for : This means the gravitational force on moon two is one fourth as large as the gravitational force on moon one.
Step 4: Select the correct option. The result matches option D.
The final answer is .
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Given: • Mass of the planet = M_p • Mass of moon one = m • Mass of moon two = m (since they have equal mass) • Radius of orbit for moon one = r_1 = r • Radius of orbit for moon two = r_2 = 2r The formula for the gravitational force F between two objec…
This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.