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A sample of a radioactive substance has an initial mass of 320 g. If its half-life is 2 minutes, how much of the substance will remain after 10 minutes?

Physics

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Answer

a. 10g\text{a. 10g}

Step-by-step solution

5 steps

let's solve this radioactive decay problem.

The formula for radioactive decay is:

N=N0(12)nN = N_0 \left( \frac{1}{2} \right)^n

where:

  • NN is the remaining mass of the radioactive material
  • N0N_0 is the initial mass of the radioactive material
  • nn is the number of half-lives that have passed
  1. Identify the given values.

    Initial mass (N0N_0) = 320 g320 \text{ g}
    Half-life (T1/2T_{1/2}) = 2 minutes2 \text{ minutes}
    Total time (tt) = 10 minutes10 \text{ minutes}

  2. Calculate the number of half-lives (nn).

    n=Total timeHalf-lifen = \frac{\text{Total time}}{\text{Half-life}} n=10 minutes2 minutesn = \frac{10 \text{ minutes}}{2 \text{ minutes}} n=5n = 5
  3. Substitute the values into the decay formula.

    N=320 g(12)5N = 320 \text{ g} \left( \frac{1}{2} \right)^5
  4. Calculate the value of (12)5\left( \frac{1}{2} \right)^5.

    (12)5=1525=132\left( \frac{1}{2} \right)^5 = \frac{1^5}{2^5} = \frac{1}{32}
  5. Calculate the remaining mass (NN).

    N=320 g×132N = 320 \text{ g} \times \frac{1}{32} N=32032 gN = \frac{320}{32} \text{ g} N=10 gN = 10 \text{ g}

    The mass remaining after 10 minutes is 10 g10 \text{ g}.

    The final answer is a. 10g\text{a. 10g}.

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