a) Specific latent heat of fusion is the amount of heat energy required to change 1 kg of a substance from…

Question

a) Specific latent heat of fusion is the amount of heat energy required to change 1 kg of a substance from its solid state to its liquid state at its melting point, without any change in t

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a) Specific latent heat of fusion is the amount of heat energy required to change 1 kg of a substance from its solid state to its liquid state at its melting point, without any change in temperature. b) i) Other than current and voltage, two measurements that would be taken in order to determine the quantity of heat absorbed by the melted ice are: 1. The mass of the melted ice (collected water). 2. The time taken for the ice to melt (duration of heating). ii) To determine the power P of the heater: Step 1: The heat energy Q absorbed by the melted ice is given by the formula: Q = mL_f where m is the mass of the melted ice and L_f is the specific latent heat of fusion of ice. Step 2: The heat energy Q supplied by the electric heater over a time t is given by the formula: Q = Pt where P is the power of the heater and t is the time duration for which the heater was on. Step 3: Assuming all the heat supplied by the heater is absorbed by the ice (no heat loss to the surroundings), we can equate the two expressions for Q: Pt = mL_f Step 4: To determine the power P of the heater, rearrange the equation: P = mL_f/t Thus, by measuring the mass of melted ice (m) and the time taken (t), and knowing the specific latent heat of fusion (L_f), the power P of the heater can be calculated.

A) Specific latent heat of fusion is the amount of heat energy required to change 1 kg of a substance from its solid state to its liquid state at its melting point, without any change in t

Step-by-step solution

Part b(i)

Part b(ii)· 4 steps

The heat energy $Q$ absorbed by the melted ice is given by the formula

The heat energy $Q$ supplied by the electric heater over a time $t$ is given by the formula

Assuming all the heat supplied by the heater is absorbed by the ice (no heat loss to the surroundings), we can equate the two expressions for $Q$

To determine the power $P$ of the heater, rearrange the equation

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