This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Two, let's knock this out. Here are the calculations for the induced EMF and induced current. Given information: Number of turns, N = 2000 Side length of the square coil, L = 150 mm = 0.15 m Initial magnetic flux density, B_1 = 0.4 T Final magnetic flux density, B_2 = 0.2 T Time interval, t = 0.8 s Total resistance of the coil, R = 4 Angle relative to the field, = 45^ Part 1: Calculate the magnitude of the induced EMF. Step 1: Calculate the area of the square coil. A = L^2 A = (0.15 m)^2 A = 0.0225 m^2 Step 2: Calculate the change in magnetic flux density. B = B_2 - B_1 B = 0.2 T - 0.4 T B = -0.2 T For magnitude, we use | B| = 0.2 T. Step 3: Calculate the magnitude of the induced EMF using Faraday's Law of Induction. The formula for induced EMF is E = -N ( )/( t), where = BA . Since the magnetic flux density changes, = B · A · . For the magnitude of EMF: |E| = N (| B| · A · )/( t) |E| = 2000 × 0.2 T × 0.0225 m^2 × (45^)0.8 s |E| = 2000 × (0.2 × 0.0225 × 0.70710678)/(0.8) |E| = 2000 × (0.0031819805)/(0.8) |E| = 2000 × 0.0039774756 |E| = 7.9549512 V Rounding to three significant figures: Magnitude of induced EMF = 7.95 V Part 2: Calculate the magnitude of the induced current. Step 1: Use Ohm's Law to find the induced current. I = |E|R I = 7.9549512 V4 I = 1.9887378 A Rounding to three significant figures: Magnitude of induced current = 1.99 A Got more? Send 'em 📸