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A swimmer heads out to swim across a river. The river flows at 0.54 m/s to the left. The swimmer swims perpendicular to the current at 0.72 m/s relative to the water. Calculate the swimmer's resultant

Physics

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Step-by-step solution

3 steps
  1. Identify the given velocities.

    The velocity of the current, v⃗c\vec{v}_c, is 0.54 m/s0.54 \text{ m/s} from right to left.
    The velocity of the swimmer relative to the water, v⃗sw\vec{v}_{sw}, is 0.72 m/s0.72 \text{ m/s} at right angles to the current.

  2. Calculate the magnitude of the swimmer's velocity relative to the river bank.

    Since the two velocities are perpendicular, we can use the Pythagorean theorem to find the magnitude of the resultant velocity, v⃗s\vec{v}_s.

    ∣v⃗s∣=∣v⃗sw∣2+∣v⃗c∣2|\vec{v}_s| = \sqrt{|\vec{v}_{sw}|^2 + |\vec{v}_c|^2} ∣v⃗s∣=(0.72 m/s)2+(0.54 m/s)2|\vec{v}_s| = \sqrt{(0.72 \text{ m/s})^2 + (0.54 \text{ m/s})^2} ∣v⃗s∣=0.5184 m2/s2+0.2916 m2/s2|\vec{v}_s| = \sqrt{0.5184 \text{ m}^2/\text{s}^2 + 0.2916 \text{ m}^2/\text{s}^2} ∣v⃗s∣=0.81 m2/s2|\vec{v}_s| = \sqrt{0.81 \text{ m}^2/\text{s}^2} ∣v⃗s∣=0.90 m/s|\vec{v}_s| = 0.90 \text{ m/s}
  3. Calculate the direction of the swimmer's velocity relative to the river bank.

    Let ϕ\phi be the angle of the swimmer's resultant velocity relative to the direction the swimmer is aiming (perpendicular to the current).

    tan⁡ϕ=velocity component parallel to currentvelocity component perpendicular to current\tan \phi = \frac{\text{velocity component parallel to current}}{\text{velocity component perpendicular to current}} tan⁡ϕ=∣v⃗c∣∣v⃗sw∣=0.54 m/s0.72 m/s\tan \phi = \frac{|\vec{v}_c|}{|\vec{v}_{sw}|} = \frac{0.54 \text{ m/s}}{0.72 \text{ m/s}} tan⁡ϕ=34=0.75\tan \phi = \frac{3}{4} = 0.75 ϕ=arctan⁡(0.75)\phi = \arctan(0.75) ϕ≈36.9∘\phi \approx 36.9^\circ

    The swimmer is swimming perpendicular to the current, and the current is flowing from right to left. Therefore, the resultant velocity will be directed 36.9∘36.9^\circ from the direction perpendicular to the current, towards the left bank (in the direction of the current).

    The magnitude of the swimmer's velocity relative to the river bank is 0.90 m/s\boxed{\text{0.90 m/s}}.
    The direction of the swimmer's velocity relative to the river bank is 36.9∘ from the direction perpendicular to the current, towards the left bank\boxed{\text{36.9}^\circ \text{ from the direction perpendicular to the current, towards the left bank}}.

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