A ticker timer vibrates at a frequency of 50 Hz. The lengths of five consecutive segments on a strip of paper are measured as follows: A=2.5 cm, B=7.5 cm, C=12.5 cm, D=17.5 cm, E=22.5 cm. Calculate th

Here's the solution to your problem:

First, let's determine the time interval for each segment.
The ticker timer operates at a frequency of $50 \text{ Hz}$.
The period ($T$) of the ticker timer, which is the time for one tick (or one dot interval), is given by:

$$T = \frac{1}{\text{frequency}} = \frac{1}{50 \text{ Hz}} = 0.02 \text{ s}$$

Each segment (A, B, C, D, E) represents the distance covered in one such time interval, $\Delta t = 0.02 \text{ s}$.

The lengths of the segments are:
$L_A = 2.5 \