This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
To calculate acceleration from a velocity-time graph, we find the gradient (slope) of the line. The formula for acceleration is: a = ( v)/( t) = final velocity - initial velocityfinal time - initial time a) Step 1: Identify initial and final points from the graph. The graph starts at (t_1, v_1) = (0 hours, 0 km/h) and ends at (t_2, v_2) = (2 hours, 30 km/h). Step 2: Calculate the change in velocity and change in time. v = 30 km/h - 0 km/h = 30 km/h t = 2 hours - 0 hours = 2 hours Step 3: Calculate the acceleration. a = 30 km/h2 hours = 15 km/h^2 The acceleration for graph a) is 15 km/h^2 b) Step 1: Identify initial and final points from the graph. The graph shows a constant velocity. Let's take (t_1, v_1) = (0 s, 15 m/s) and (t_2, v_2) = (4 s, 15 m/s). Step 2: Calculate the change in velocity and change in time. v = 15 m/s - 15 m/s = 0 m/s t = 4 s - 0 s = 4 s Step 3: Calculate the acceleration. a = 0 m/s4 s = 0 m/s^2 The acceleration for graph b) is 0 m/s^2 c) Step 1: Identify initial and final points from the graph. The graph starts at (t_1, v_1) = (0 s, 25 m/s) and ends at (t_2, v_2) = (4 s, 0 m/s). Step 2: Calculate the change in velocity and change in time. v = 0 m/s - 25 m/s = -25 m/s t = 4 s - 0 s = 4 s Step 3: Calculate the acceleration. a = -25 m/s4 s = -6.25 m/s^2 The acceleration for graph c) is -6.25 m/s^2 Drop the next question 📸