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Aminas tempreture as measured at the School gate was 36.2°C. What was her tempreture in SI units? Calculate the density of a wooden block that has a volume of 25 cm³ and a mass of 15g. Give your answer in SI units. Copy the table below in your exercise book and complete it-

Physics

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Here are the solutions to the problems.

1) Amina's temperature in SI units

  1. The SI unit for temperature is Kelvin (K).

    To convert from Celsius to Kelvin, add 273.15 to the Celsius temperature.

    TK=T∘C+273.15T_{\text{K}} = T_{^\circ\text{C}} + 273.15
  2. Substitute the given temperature into the formula.

    TK=36.2+273.15T_{\text{K}} = 36.2 + 273.15
  3. Calculate the temperature in Kelvin.

    TK=309.35 KT_{\text{K}} = 309.35\ \text{K}

    Amina's temperature in SI units is 309.35 K\boxed{\text{309.35 K}}.

    2) Density of the wooden block in SI units

  4. Convert the mass from grams to kilograms (SI unit for mass).

    m=15 g×1 kg1000 g=0.015 kgm = 15\ \text{g} \times \frac{1\ \text{kg}}{1000\ \text{g}} = 0.015\ \text{kg}
  5. Convert the volume from cubic centimeters to cubic meters (SI unit for volume).

    V=25 cm3×(1 m100 cm)3=25 cm3×1 m31,000,000 cm3=0.000025 m3V = 25\ \text{cm}^3 \times \left(\frac{1\ \text{m}}{100\ \text{cm}}\right)^3 = 25\ \text{cm}^3 \times \frac{1\ \text{m}^3}{1,000,000\ \text{cm}^3} = 0.000025\ \text{m}^3
  6. Use the formula for density, ρ=mV\rho = \frac{m}{V}.

    ρ=0.015 kg0.000025 m3\rho = \frac{0.015\ \text{kg}}{0.000025\ \text{m}^3}
  7. Calculate the density.

    ρ=600 kg/m3\rho = 600\ \text{kg/m}^3

    The density of the wooden block in SI units is 600 kg/m3\boxed{\text{600 kg/m}^3}.

    3) Complete the table of SI units

    Here is the completed table:

    QuantitySI Unit
    AreaMetre Squared (m2\text{m}^2)
    VolumeMetre Cubed (m3\text{m}^3)
    TimeSecond (s)
    MassKilogram (kg)
    Electric currentAmpere (A)
    LengthMetre (m)
    TemperatureKelvin (K)
    DensityKilogram per cubic meter (kg/m3\text{kg/m}^3)
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