An object of mass 2 kg moves with a uniform speed of 10 ms⁻¹ for 5 s along a straight path. Determine the magnitude of its acceleration. 0 ms⁻² 1.0 ms⁻² 3.0 ms⁻² 4.0 ms⁻²

Hey Rofeehat, good to see you again.

a) Step 1: Identify the given information. The object moves with a uniform speed. Uniform speed means that the velocity of the object is constant.

Step 2: Recall the definition of acceleration. Acceleration is defined as the rate of change of velocity. $a = \frac{\Delta v}{\Delta t}$ where $\Delta v$ is the change in velocity and $\Delta t$ is the change in time.

Step 3: Determine the change in velocity. Since the speed is uniform, the velocity does not change. Therefore, the change in velocity ($\Delta v$) is zero. $\Delta v = 0 ms^{-1}$

Step 4: Calculate the acceleration. Substitute $\Delta v = 0$ into the acceleration formula. $a = \frac{0 ms^{-1}}{5 s} = 0 ms^{-2}$

The magnitude of its acceleration is $0 ms^{-2}$.

The correct option is (a). $\boxed{(a) 0 ms^{-2}}$ Send me the next one 📸