An object of mass 2 kg moves with a uniform speed of 10 ms⁻¹ for 5 s along a straight path. Determine the magnitude of its acceleration. 0 ms⁻² 1.0 ms⁻² 3.0 ms⁻² 4.0 ms⁻²

Physics

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Answer

A

Step-by-step solution

4 steps

a)

  1. Identify the given information.

    The object moves with a uniform speed. Uniform speed means that the velocity of the object is constant.

  2. Recall the definition of acceleration.

    Acceleration is defined as the rate of change of velocity.

    a=ΔvΔta = \frac{\Delta v}{\Delta t}

    where Δv\Delta v is the change in velocity and Δt\Delta t is the change in time.

  3. Determine the change in velocity.

    Since the speed is uniform, the velocity does not change. Therefore, the change in velocity (Δv\Delta v) is zero.

    Δv=0 ms−1\Delta v = 0 \text{ ms}^{-1}
  4. Calculate the acceleration.

    Substitute Δv=0\Delta v = 0 into the acceleration formula.

    a=0 ms−15 s=0 ms−2a = \frac{0 \text{ ms}^{-1}}{5 \text{ s}} = 0 \text{ ms}^{-2}

    The magnitude of its acceleration is 0 ms−20 \text{ ms}^{-2}.

    The correct option is (a).

    (a) 0 ms−2\boxed{\text{(a) } 0 \text{ ms}^{-2}}
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