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• Boyle's Law: For a fixed mass of gas at constant temperature, the pressure of the gas is inversely proportional to its volume. Mathematically, P (1)/(V) or PV = constant.

Physics

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  • Boyle's Law: For a fixed mass of gas at constant temperature, the pressure of the gas is inversely proportional to its volume. Mathematically, P∝1VP \propto \frac{1}{V} or PV=constantPV = \text{constant}.
  • Charles' Law: For a fixed mass of gas at constant pressure, the volume of the gas is directly proportional to its absolute temperature. Mathematically, V∝TV \propto T or VT=constant\frac{V}{T} = \text{constant}.
  • Pressure Law (also known as Gay-Lussac's Law): For a fixed mass of gas at constant volume, the pressure of the gas is directly proportional to its absolute temperature. Mathematically, P∝TP \propto T or PT=constant\frac{P}{T} = \text{constant}.

To calculate the pressure exerted by the gas and state the General Gas Equation:

  1. Convert the given temperatures from Celsius to Kelvin.

    T1=27∘C+273=300 KT_1 = 27^\circ\text{C} + 273 = 300 \text{ K} T2=90∘C+273=363 KT_2 = 90^\circ\text{C} + 273 = 363 \text{ K}
  2. Identify the given initial pressure.

    P1=80 mmHgP_1 = 80 \text{ mmHg}
  3. Since the volume is maintained at constant, we use the Pressure Law (Gay-Lussac's Law), which states that P1T1=P2T2\frac{P_1}{T_1} = \frac{P_2}{T_2}.

    Rearrange to solve for P2P_2.

    P2=P1×T2T1P_2 = P_1 \times \frac{T_2}{T_1}
  4. Substitute the values and calculate the final pressure.

    P2=80 mmHg×363 K300 KP_2 = 80 \text{ mmHg} \times \frac{363 \text{ K}}{300 \text{ K}} P2=80×1.21 mmHgP_2 = 80 \times 1.21 \text{ mmHg} P2=96.8 mmHgP_2 = 96.8 \text{ mmHg}

    The pressure exerted by the gas is 96.8 mmHg\boxed{\text{96.8 mmHg}}.

  5. State the General Gas Equation.

    The General Gas Equation combines Boyle's Law, Charles' Law, and the Pressure Law. It is given by:

    P1V1T1=P2V2T2\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}
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