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State Boyle's law -- It states that at constant temperature of a fixed mass of a gas is inversely proportional to its volume. (b) A gas occupies 500cm³ at 27°C and 100,000 Pa. What will be its volume at 0°C and 101,325 Pa?

Physics

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Answer

b

449.03 cm3\text{449.03 cm}^3

Step-by-step solution

4 steps

Haya McCarthy, twende na swali la 1.

Part a

Sheria ya Boyle inasema kwamba kwa kiasi fulani cha gesi kwenye halijoto isiyobadilika, shinikizo ni kinyume cha uwiano na ujazo wake.

Part b

449.03 cm3\text{449.03 cm}^3

Ili kutatua hili, tutatumia Sheria ya Gesi Iliyounganishwa (Combined Gas Law) kwa sababu shinikizo, ujazo na halijoto zote zinabadilika.

  1. Badilisha halijoto kutoka Selsiasi kwenda Kelvin.

    Halijoto katika sheria za gesi lazima iwe katika Kelvin.

    T1=27∘C+273=300 KT_1 = 27^\circ\text{C} + 273 = 300 \text{ K} T2=0∘C+273=273 KT_2 = 0^\circ\text{C} + 273 = 273 \text{ K}
  2. Andika Sheria ya Gesi Iliyounganishwa.

    Sheria ya Gesi Iliyounganishwa inasema:

    P1V1T1=P2V2T2\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

    Ambapo:
    P1=100,000 PaP_1 = 100,000 \text{ Pa}
    V1=500 cm3V_1 = 500 \text{ cm}^3
    T1=300 KT_1 = 300 \text{ K}
    P2=101,325 PaP_2 = 101,325 \text{ Pa}
    T2=273 KT_2 = 273 \text{ K}
    V2=?V_2 = ?

  3. Panga upya fomula ili kupata V2V_2.

    V2=P1V1T2P2T1V_2 = \frac{P_1V_1T_2}{P_2T_1}
  4. Badilisha namba kwenye fomula na ukokotoe.

    V2=(100,000 Pa)(500 cm3)(273 K)(101,325 Pa)(300 K)V_2 = \frac{(100,000 \text{ Pa})(500 \text{ cm}^3)(273 \text{ K})}{(101,325 \text{ Pa})(300 \text{ K})} V2=13,650,000,000 Pa⋅cm3⋅K30,397,500 Pa⋅KV_2 = \frac{13,650,000,000 \text{ Pa} \cdot \text{cm}^3 \cdot \text{K}}{30,397,500 \text{ Pa} \cdot \text{K}} V2≈449.03 cm3V_2 \approx 449.03 \text{ cm}^3

    Ujazo mpya wa gesi utakuwa:

    449.03 cm3\boxed{\text{449.03 cm}^3}
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