Complete the table and plot a graph of 1/I against 1/l using the provided data.

a) Complete the table including values of $\frac{1}{l}$ and $\frac{1}{I}$.

Step 1: Calculate $\frac{1}{l}$ for each value of $l$.

Step 2: Calculate $\frac{1}{I}$ for each value of $I$.
Round values to two decimal places for the table.

$l(\text{m})$	$I(\text{A})$	$\frac{1}{l} (\text{m}^{-1})$	$\frac{1}{I} (\text{A}^{-1})$
0.700	0.40	1.43	2.50
0.600	0.44	1.67	2.27
0.500	0.50	2.00	2.00
0.400	0.58	2.50	1.72
0.300	0.70	3.33	1.43
0.200	0.86	5.00	1.16

b) Plot a graph of $\frac{1}{I}$ against $\frac{1}{l}$.

To plot the graph:

• Draw a set of axes. Label the y-axis as $\frac{1}{I} (\text{A}^{-1})$ and the x-axis as $\frac{1}{l} (\text{m}^{-1})$.
• Choose appropriate scales for both axes to accommodate the range of values from the completed table.
• Plot the points from the table: $(1.43, 2.50)$, $(1.67, 2.27)$, $(2.00, 2.00)$, $(2.50, 1.72)$, $(3.33, 1.43)$, and $(5.00, 1.16)$.
• Draw the best-fit straight line through the plotted points.

c) Find the slope, S of the graph.

Step 1: Choose two points from the best-fit line. For calculation purposes, we will use the first and last data points from the table for maximum accuracy.
Point 1: $(\frac{1}{l}_1, \frac{1}{I}_1) = (\frac{1}{0.700}, \frac{1}{0.40}) = (1.42857, 2.50)$
Point 2: $(\frac{1}{l}_2, \frac{1}{I}_2) = (\frac{1}{0.200}, \frac{1}{0.86}) = (5.00, 1.16279)$

Step 2: Calculate the slope using the formula $S = \frac{\Delta (\frac{1}{I})}{\Delta (\frac{1}{l})}$.

$$$$