Calculate the current that must be passed into a solution of aluminum salt for 2hrs in order to deposit 2.5g of aluminum? An example of insoluble chloride im water is: SO₂ can be used as: If the mass number of X is 24 and X²+ contains 10 electrons, the nucleus will consist of

Physics

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1. Calculate the current that must be passed into a solution of aluminum salt for 2hrs in order to deposit 2.5g of aluminum?

  1. Identify the given values and constants.

    • Mass of aluminum (mm) = 2.5 g2.5 \, \text{g}
    • Time (tt) = 2 hrs2 \, \text{hrs}
    • Molar mass of aluminum (MM) = 26.98 g/mol26.98 \, \text{g/mol} (approximately 27 g/mol27 \, \text{g/mol})
    • Charge of aluminum ion (zz) = 3 (since aluminum forms Al3+\text{Al}^{3+})
    • Faraday's constant (FF) = 96485 C/mol96485 \, \text{C/mol}
  2. Convert time from hours to seconds.

    t=2 hrs×60 min1 hr×60 s1 min=7200 st = 2 \, \text{hrs} \times \frac{60 \, \text{min}}{1 \, \text{hr}} \times \frac{60 \, \text{s}}{1 \, \text{min}} = 7200 \, \text{s}
  3. Use Faraday's first law of electrolysis to calculate the current (II).

    The formula is m=ItMzFm = \frac{ItM}{zF}. Rearrange to solve for II:

    I=mzFMtI = \frac{mzF}{Mt}

    Substitute the values:

    I=(2.5 g)×3×(96485 C/mol)(26.98 g/mol)×(7200 s)I = \frac{(2.5 \, \text{g}) \times 3 \times (96485 \, \text{C/mol})}{(26.98 \, \text{g/mol}) \times (7200 \, \text{s})} I=723637.5 C194256 sI = \frac{723637.5 \, \text{C}}{194256 \, \text{s}} I≈3.725 AI \approx 3.725 \, \text{A}

    The current required is 3.73 A\boxed{\text{3.73 A}}.

    2. An example of insoluble chloride in water is:

    An example of an insoluble chloride in water is silver chloride (AgCl\text{AgCl}). Other examples include lead(II) chloride (PbCl2\text{PbCl}_2) and mercury(I) chloride (Hg2Cl2\text{Hg}_2\text{Cl}_2).

    3. SO₂ can be used as:

    SO2\text{SO}_2 (sulfur dioxide) can be used as a preservative (e.g., in wines and dried fruits) and as a bleaching agent (e.g., for wool and silk).

    4. If the mass number of X is 24 and X²⁺ contains 10 electrons, the nucleus will consist of:

  4. Determine the number of protons.

    • The ion X2+\text{X}^{2+} has 10 electrons.
    • Since it has a +2+2 charge, it has lost 2 electrons.
    • Therefore, the neutral atom X must have had 10+2=1210 + 2 = 12 electrons.
    • In a neutral atom, the number of electrons equals the number of protons. So, the number of protons in X is 12.
  5. Determine the number of neutrons.

    • The mass number (A) is given as 24.
    • The mass number is the sum of protons (Z) and neutrons (N): A=Z+NA = Z + N.
    • We found the number of protons (Z) to be 12.
    24=12+N24 = 12 + N N=24−12N = 24 - 12 N=12N = 12

    The nucleus of X will consist of 12 protons and 12 neutrons\boxed{\text{12 protons and 12 neutrons}}.

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