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Calculate the energy contribution from each nutrient.

Physics

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Answer

Carbohydrates

375 g\text{375 g}

Fat

83.33 g\text{83.33 g}

Protein

62.5 g\text{62.5 g}

Step-by-step solution

2 steps

Here's the solution for question 2(a)(ii):

  1. Calculate the energy contribution from each nutrient.

    The total daily energy need is 2500 Kcal2500 \text{ Kcal}.
    Energy from carbohydrates:

    0.60×2500 Kcal=1500 Kcal0.60 \times 2500 \text{ Kcal} = 1500 \text{ Kcal}

    Energy from fat:

    0.30×2500 Kcal=750 Kcal0.30 \times 2500 \text{ Kcal} = 750 \text{ Kcal}

    Energy from protein:

    0.10×2500 Kcal=250 Kcal0.10 \times 2500 \text{ Kcal} = 250 \text{ Kcal}
  2. Calculate the quantity (in grams) of each nutrient.

    Standard energy values are approximately 4 Kcal/g4 \text{ Kcal/g} for carbohydrates, 9 Kcal/g9 \text{ Kcal/g} for fat, and 4 Kcal/g4 \text{ Kcal/g} for protein.
    Quantity of carbohydrates:

    1500 Kcal4 Kcal/g=375 g\frac{1500 \text{ Kcal}}{4 \text{ Kcal/g}} = 375 \text{ g}

    Quantity of fat:

    750 Kcal9 Kcal/g≈83.33 g\frac{750 \text{ Kcal}}{9 \text{ Kcal/g}} \approx 83.33 \text{ g}

    Quantity of protein:

    250 Kcal4 Kcal/g=62.5 g\frac{250 \text{ Kcal}}{4 \text{ Kcal/g}} = 62.5 \text{ g}

    The quantities of each nutrient needed are:

    • Carbohydrates: 375 g\boxed{\text{375 g}}
    • Fat: 83.33 g\boxed{\text{83.33 g}}
    • Protein: 62.5 g\boxed{\text{62.5 g}}
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