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Calculate the escape velocity from Earth using the formula v_e = sqrt(2gR) with g=9.8 m/s2 and R=6.4 x 106 m.

Physics

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Step-by-step solution

4 steps

To calculate the escape velocity, we use the formula:

ve=2gRv_e = \sqrt{2gR}

where:

  • vev_e is the escape velocity
  • gg is the acceleration due to gravity on the Earth's surface (9.8 m/s29.8 \text{ m/s}^2)
  • RR is the radius of the Earth (6.4×106 m6.4 \times 10^6 \text{ m})
  1. Substitute the given values into the formula.

    ve=2×9.8 m/s2×6.4×106 mv_e = \sqrt{2 \times 9.8 \text{ m/s}^2 \times 6.4 \times 10^6 \text{ m}}
  2. Perform the multiplication inside the square root.

    ve=19.6 m/s2×6.4×106 mv_e = \sqrt{19.6 \text{ m/s}^2 \times 6.4 \times 10^6 \text{ m}} ve=125.44×106 m2/s2v_e = \sqrt{125.44 \times 10^6 \text{ m}^2/\text{s}^2}
  3. Calculate the square root.

    ve=125.44×106 m/sv_e = \sqrt{125.44} \times \sqrt{10^6} \text{ m/s} ve≈11.20×103 m/sv_e \approx 11.20 \times 10^3 \text{ m/s} ve≈11200 m/sv_e \approx 11200 \text{ m/s}
  4. Convert the velocity from meters per second (m/s) to kilometers per second (km/s).

    ve=11200 m/s×1 km1000 mv_e = 11200 \text{ m/s} \times \frac{1 \text{ km}}{1000 \text{ m}} ve≈11.2 km/sv_e \approx 11.2 \text{ km/s}

    Comparing this value to the given options:
    A. 25.3 km/s25.3 \text{ km/s}
    B. 4.2 km/s4.2 \text{ km/s}
    C. 4.0 km/s4.0 \text{ km/s}
    D. 11.3 km/s11.3 \text{ km/s}

    The calculated escape velocity of 11.2 km/s11.2 \text{ km/s} is closest to option D.

    The final answer is D. 11.3 km/s\boxed{\text{D. } 11.3 \text{ km/s}}.

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