First, let's describe the velocity-time graph.

This is the distance covered during the acceleration phase (first 5 seconds). On a velocity-time graph, distance is the area under the graph. For this phase, the area is a triangle.

The total distance is the sum of the distances covered in all three phases.

• Distance in Phase 1 (acceleration, $d_1$): Calculated above: $d_1 = 100 \text{ m}$.

• Distance in Phase 2 (constant velocity, $d_2$): This is a rectangle on the graph. Velocity $= 40 \text{ m/s}$ Time $= 10 \text{ s}$

  $$d_2 = \text{velocity} \times \text{time}$$ $$d_2 = 40 \text{ m/s} \times 10 \text{ s}$$ $$d_2 = 400 \text{ m}$$

• Distance in Phase 3 (retardation, $d_3$): This is a triangle on the graph. Base $= 5 \text{ s}$ Height $= 40 \text{ m/s}$

  $$d_3 = \frac{1}{2} \times \text{base} \times \text{height}$$ $$d_3 = \frac{1}{2} \times 5 \text{ s} \times 40 \text{ m/s}$$ $$d_3 = 100 \text{ m}$$