We read your photo as:

For the common-base configuration of Fig. 5.165, determine re given RB = 6.8 k RC = 4.7 k alpha = 0.998, gos = 10 . The transistor is a PNP type. Assume VEB = 0.7 V and VT = 25 mV.

Physics

ScanSolve AI Answer


: For the common-base configuration of Fig. 5.165:
Given: RB=6.8 kΩR_B = 6.8 \, \text{k}\Omega, RC=4.7 kΩR_C = 4.7 \, \text{k}\Omega, α=0.998\alpha = 0.998, gos=10 μSg_{os} = 10 \, \mu\text{S}.
The transistor is a PNP type (arrow points inward).
Assume VEB=0.7 VV_{EB} = 0.7 \, \text{V} for a silicon transistor and VT=25 mVV_T = 25 \, \text{mV} at room temperature.

a. Determine rer_e

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp