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Calculate the future and past height of Mount Everest given its current height and growth rate.

Physics

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Here are the solutions to the plate movement calculations:

Question 1: Plate movement calculation
Given:
Current height of Mount Everest = 8,849 m
Growth rate = 5 cm per year = 0.05 m per year
Assumption: "Currently" refers to the year 2023 for calculations involving specific years.

a) What will be the height in 2082? (one decimal place)

  1. Calculate the number of years from 2023 to 2082.

    Years=2082−2023=59 years\text{Years} = 2082 - 2023 = 59 \text{ years}
  2. Calculate the total height increase over these years.

    Height increase=59 years×0.05 m/year=2.95 m\text{Height increase} = 59 \text{ years} \times 0.05 \text{ m/year} = 2.95 \text{ m}
  3. Add the increase to the current height and round to one decimal place.

    Height in 2082=8,849 m+2.95 m=8,851.95 m\text{Height in 2082} = 8,849 \text{ m} + 2.95 \text{ m} = 8,851.95 \text{ m} 8,852.0 m\boxed{\text{8,852.0 m}}

    b) What would be the average height of Mount Everest in 1901? (one decimal place)

  4. Calculate the number of years from 1901 to 2023.

    Years ago=2023−1901=122 years\text{Years ago} = 2023 - 1901 = 122 \text{ years}
  5. Calculate the total height decrease over these years.

    Height decrease=122 years×0.05 m/year=6.1 m\text{Height decrease} = 122 \text{ years} \times 0.05 \text{ m/year} = 6.1 \text{ m}
  6. Subtract the decrease from the current height and round to one decimal place.

    Height in 1901=8,849 m−6.1 m=8,842.9 m\text{Height in 1901} = 8,849 \text{ m} - 6.1 \text{ m} = 8,842.9 \text{ m} 8,842.9 m\boxed{\text{8,842.9 m}}

    c) How long will it take Mt Everest to reach 8,851 m?

  7. Calculate the required height increase.

    Required increase=8,851 m−8,849 m=2 m\text{Required increase} = 8,851 \text{ m} - 8,849 \text{ m} = 2 \text{ m}
  8. Calculate the time needed to achieve this increase.

    Time=2 m0.05 m/year=40 years\text{Time} = \frac{2 \text{ m}}{0.05 \text{ m/year}} = 40 \text{ years} 40 years\boxed{\text{40 years}}

    d) What is the projected year for the mountain to reach 8,851 m in height?

  9. Use the time calculated in part (c) and the assumed current year (2023).

    Projected year=2023+40 years=2063\text{Projected year} = 2023 + 40 \text{ years} = 2063 2063\boxed{\text{2063}}

    Question 2: Plate movement
    Given:
    YT and KB are on opposite sides of a transform boundary.
    Each moves at a rate of 1.5 cm per year in opposed directions.
    Relative speed = 1.5 cm/year+1.5 cm/year=3 cm/year=0.03 m/year1.5 \text{ cm/year} + 1.5 \text{ cm/year} = 3 \text{ cm/year} = 0.03 \text{ m/year}.
    Current distance between them = 25 meters.
    Assumption: "Now" refers to the year 2023 for calculations involving specific years.

    a) How long will it take for them to be 55 meters apart? (Answers should be in whole numbers)

  10. Calculate the additional distance they need to move apart.

    Additional distance=55 m−25 m=30 m\text{Additional distance} = 55 \text{ m} - 25 \text{ m} = 30 \text{ m}
  11. Calculate the time required for this movement.

    Time=30 m0.03 m/year=1000 years\text{Time} = \frac{30 \text{ m}}{0.03 \text{ m/year}} = 1000 \text{ years} 1000 years\boxed{\text{1000 years}}

    b) What will be the distance between the two neighbours in 2045?

  12. Calculate the number of years from 2023 to 2045.

    Years=2045−2023=22 years\text{Years} = 2045 - 2023 = 22 \text{ years}
  13. Calculate the distance increased over these years.

    Distance increased=22 years×0.03 m/year=0.66 m\text{Distance increased} = 22 \text{ years} \times 0.03 \text{ m/year} = 0.66 \text{ m}
  14. Add the increased distance to the current distance.

    Distance in 2045=25 m+0.66 m=25.66 m\text{Distance in 2045} = 25 \text{ m} + 0.66 \text{ m} = 25.66 \text{ m} 25.66 m\boxed{\text{25.66 m}}

    c) What will be the projected distance between them in 17-years from now?

  15. Calculate the distance increased over 17 years.

    Distance increased=17 years×0.03 m/year=0.51 m\text{Distance increased} = 17 \text{ years} \times 0.03 \text{ m/year} = 0.51 \text{ m}
  16. Add the increased

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