Given y = A sin(2000t - (pi/16)x), calculate wavelength, frequency, and speed of the wave.

The wave number $k$ is related to the wavelength $\lambda$ by the formula $k = \frac{2\pi}{\lambda}$.
Rearranging for $\lambda$:

$$\lambda = \frac{2\pi}{k}$$

Substitute the value of $k$:

$$\lambda = \frac{2\pi}{\frac{\pi}{16}}$$ $$\lambda = 2\pi \times \frac{16}{\pi}$$ $$\lambda = 32\, \text{m}$$

The wavelength is $\boxed{\text{32 m}}$.

The angular frequency $\omega$ is related to the frequency $f$ by the formula $\omega = 2\pi f$.
Rearranging for $f$:

$$f = \frac{\omega}{2\pi}$$

Substitute the value of $\omega$:

$$f = \frac{2000}{2\pi}$$ $$f = \frac{1000}{\pi}\, \text{Hz}$$

Using $\pi \approx 3.142$:

$$f \approx \frac{1000}{3.142} \approx 318.3\, \text{Hz}$$

The frequency is $\boxed{\text{318.3 Hz}}$.

The speed of the wave $v$ can be calculated using the formula $v = \frac{\omega}{k}$.
Substitute the values of $\omega$ and $k$:

$$v = \frac{2000}{\frac{\pi}{16}}$$ $$v = 2000 \times \frac{16}{\pi}$$ $$v = \frac{32000}{\pi}\, \text{m/s}$$

Using $\pi \approx 3.142$:

$$v \approx \frac{32000}{3.142} \approx 10184.6\, \text{m/s}$$

The speed of the wave is $\boxed{\text{10184.6 m/s}}$.

The period $T$ is the reciprocal of the frequency $f$:

$$T = \frac{1}{f}$$

Substitute the exact value of $f$:

$$T = \frac{1}{\frac{1000}{\pi}}$$ $$T = \frac{\pi}{1000}\, \text{s}$$

Using $\pi \approx 3.142$:

$$T \approx \frac{3.142}{1000} \approx 0.003142\, \text{s}$$

The period is $\boxed{\text{0.003142 s}}$.