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Identify the initial vertical velocity component.

Physics

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Q8 (a): Show that the maximum height of a projectile is given by H=u2sin⁡2θ2gH = \frac{u^2 \sin^2 \theta}{2g}.

  1. Identify the initial vertical velocity component.

    The initial velocity uu is at an angle θ\theta to the horizontal. The vertical component of the initial velocity is uy=usin⁡θu_y = u \sin \theta.

  2. Apply a kinematic equation for vertical motion.

    At the maximum height, the vertical velocity vyv_y is 0. Using the kinematic equation vy2=uy2+2ayHv_y^2 = u_y^2 + 2a_y H, where ay=−ga_y = -g (acceleration

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