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Resolve the initial velocity into horizontal and vertical components.

Physics

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2 steps

a) Calculate the velocity at which the ball hits the court.

  1. Resolve the initial velocity into horizontal and vertical components.

    The initial velocity is u=60 m/su = 60 \, \text{m/s} at an angle θ=10∘\theta = 10^\circ to the horizontal.
    The horizontal component (uxu_x) remains constant throughout the flight.
    The vertical component (uyu_y) is affected by gravity.

    ux=ucos⁡θ=60 m/s×cos⁡(10∘)≈59.088 m/su_x = u \cos \theta = 60 \, \text{m/s} \times \cos(10^\circ) \approx 59.088 \, \text{m/s} uy=usin⁡θ=60 m/s×sin⁡(10∘)≈10.419 m/su_y = u \sin \theta = 60 \, \text{m/s} \times \sin(10^\circ) \approx 10.419 \, \text{m/s}
  2. Determine the final vertical velocity component (vyv_y).

    We use the kinematic equation vy2=uy2+2asyv_y^2 = u_y^2 + 2as_y.
    Taking upward as the positive direction:
    The acceleration due to gravity is a=−g=−9.8 m/s2a = -g = -9.8 \, \text{m/s}^2.
    The vertical displacement

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