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Calculate the impulse experienced by a 60 kg patient hitting a surface with an initial velocity of 1 m/s and coming to a stop.

May 1, 2026Physics

ScanSolve AI Answer

Answer

\text{-60 kg} \cdot \text{m/s}

4 steps

Identify the given values.
The mass of the patient is $m = 60\, \text{kg}$ .
The initial velocity upon impact is $v_i = 1\, \text{m/s}$ .
The final velocity after stopping is $v_f = 0\, \text{m/s}$ .
State the formula for impulse.
Impulse ( $J$ ) is the change in momentum, given by the formula:
$J = m(v_f - v_i)$
Substitute the values into the formula.
$J = 60\, \text{kg} \times (0\, \text{m/s} - 1\, \text{m/s})$
Calculate the impulse.
$J = 60\, \text{kg} \times (-1\, \text{m/s})$ $J = -60\, \text{kg} \cdot \text{m/s}$
The negative sign indicates that the impulse is in the opposite direction to the initial motion. The magnitude of the impulse is $60\, \text{kg} \cdot \text{m/s}$ .

The impulse experienced is $\text{-60 kg} \cdot \text{m/s}$ .