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In a hydraulic system a force of 400N is applied to a piston of an area 0.0004 m. (a) Calculate the pressure transmitted through the rake fluid. (b) Calculate the force ofa piston of area 0.002 m that is connected to the system

Physics

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Answers

2 parts
a

1,000,000 Pa1,000,000 \, \text{Pa}

b

2,000 N2,000 \, \text{N}

Step-by-step solution

6 steps

Part a· 3 steps

  1. Identify the given values for force and area.

    The applied force is F=400 NF = 400 \, \text{N}.
    The area of the piston is A=0.0004 m2A = 0.0004 \, \text{m}^2. (Assuming "0.0004 m" is a typo and refers to area in m2^2).

  2. Use the formula for pressure, P=FAP = \frac{F}{A}.

    P=400 N0.0004 m2P = \frac{400 \, \text{N}}{0.0004 \, \text{m}^2}
  3. Calculate the pressure.

    P=1,000,000 PaP = 1,000,000 \, \text{Pa}

    The pressure transmitted through the fluid is 1,000,000 Pa\boxed{1,000,000 \, \text{Pa}}.

Part b

2,000 N2,000 \, \text{N}

  1. Identify the pressure transmitted (from part a) and the new area.

    According to Pascal's principle, the pressure is transmitted equally throughout the hydraulic fluid. So, P=1,000,000 PaP = 1,000,000 \, \text{Pa}.
    The area of the second piston is A2=0.002 m2A_2 = 0.002 \, \text{m}^2. (Assuming "0.002 m" is a typo and refers to area in m2^2).

  2. Use the formula for force, F2=P×A2F_2 = P \times A_2.

    F2=1,000,000 Pa×0.002 m2F_2 = 1,000,000 \, \text{Pa} \times 0.002 \, \text{m}^2
  3. Calculate the force on the second piston.

    F2=2,000 NF_2 = 2,000 \, \text{N}

    The force on the piston of area 0.002 m20.002 \, \text{m}^2 is 2,000 N\boxed{2,000 \, \text{N}}.

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