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The ram of a hydraulic press developed a force of 780 N when a pressure of 150 N is exerted on the plunger with a diameter of 90 mm. Calculate the diameter of the ram in (mm). Calculate the fluid pressure.

Physics

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1.1.1 Calculate the diameter of the ram in (mm).

  1. Calculate the area of the plunger.

    The diameter of the plunger (dPd_P) is 90 mm90 \text{ mm}, which is 0.09 m0.09 \text{ m}.
    The area of the plunger (APA_P) is given by the formula A=πd24A = \frac{\pi d^2}{4}.

    AP=π(0.09 m)24=π×0.0081 m24≈0.0063617 m2A_P = \frac{\pi (0.09 \text{ m})^2}{4} = \frac{\pi \times 0.0081 \text{ m}^2}{4} \approx 0.0063617 \text{ m}^2
  2. Calculate the fluid pressure.

    The force on the plunger (FPF_P) is 150 N150 \text{ N}.
    The fluid pressure (PP) is given by P=FPAPP = \frac{F_P}{A_P}.

    P=150 N0.0063617 m2≈23578.9 PaP = \frac{150 \text{ N}}{0.0063617 \text{ m}^2} \approx 23578.9 \text{ Pa}
  3. Calculate the area of the ram.

    The force developed by the ram (FRF_R) is 780 N780 \text{ N}. According to Pascal's principle, the pressure is uniform throughout the fluid, so the pressure on the ram is also PP.
    The area of the ram (ARA_R) is given by AR=FRPA_R = \frac{F_R}{P}.

    AR=780 N23578.9 Pa≈0.033089 m2A_R = \frac{780 \text{ N}}{23578.9 \text{ Pa}} \approx 0.033089 \text{ m}^2
  4. Calculate the diameter of the ram and convert to millimeters.

    The diameter of the ram (dRd_R) is given by dR=4ARπd_R = \sqrt{\frac{4 A_R}{\pi}}.

    dR=4×0.033089 m2π=0.04218 m2≈0.20538 md_R = \sqrt{\frac{4 \times 0.033089 \text{ m}^2}{\pi}} = \sqrt{0.04218 \text{ m}^2} \approx 0.20538 \text{ m}

    Converting to millimeters:

    dR=0.20538 m×1000 mm/m≈205.38 mmd_R = 0.20538 \text{ m} \times 1000 \text{ mm/m} \approx 205.38 \text{ mm}

    The diameter of the ram is 205.38 mm\boxed{\text{205.38 mm}}.

    1.1.2 Calculate the fluid pressure.

    The fluid pressure was calculated in Step 2 of 1.1.1.

    P≈23578.9 PaP \approx 23578.9 \text{ Pa}

    The fluid pressure is 23578.9 Pa\boxed{\text{23578.9 Pa}}.

    1.2 Calculate the number of teeth of gear Y.

  5. Identify the gear ratios for each meshing pair.

    For gears W and X: NXNW=TWTX\frac{N_X}{N_W} = \frac{T_W}{T_X}
    For gears Y and Z: NZNY=TYTZ\frac{N_Z}{N_Y} = \frac{T_Y}{T_Z}

  6. Relate the speeds of the compound shaft.

    Gears X and Y are on the same shaft, so their rotational speeds are equal: NX=NYN_X = N_Y.

  7. Combine the equations to solve for TYT_Y.

    We know NW=1800 r/minN_W = 1800 \text{ r/min} (input speed) and NZ=25 r/minN_Z = 25 \text{ r/min} (output speed).
    From the gear ratio equations:
    NX=NWTWTXN_X = N_W \frac{T_W}{T_X}
    NY=NZTZTYN_Y = N_Z \frac{T_Z}{T_Y}
    Since NX=NYN_X = N_Y:

    NWTWTX=NZTZTYN_W \frac{T_W}{T_X} = N_Z \frac{T_Z}{T_Y}

    Rearrange to solve for TYT_Y:

    TY=NZ×TZ×TXNW×TWT_Y = \frac{N_Z \times T_Z \times T_X}{N_W \times T_W}
  8. Substitute the given values and calculate TYT_Y.

    NW=1800 r/minN_W = 1800 \text{ r/min}
    NZ=25 r/minN_Z = 25 \text{ r/min}
    TW=20T_W = 20 teeth
    TX=120T_X = 120 teeth
    TZ=160T_Z = 160 teeth

    TY=25 r/min×160 teeth×120 teeth1800 r/min×20 teethT_Y = \frac{25 \text{ r/min} \times 160 \text{ teeth} \times 120 \text{ teeth}}{1800 \text{ r/min} \times 20 \text{ teeth}} TY=48000036000=13.333...T_Y = \frac{480000}{36000} = 13.333...

    Since the number of teeth must be a whole number, there might be a slight rounding in the problem's given speeds or teeth counts, or it implies a non-integer ratio. However, in practical gear design, teeth are integers. If we assume the values are exact, the result is not an integer. Let's recheck the calculation.
    25×160×120=48000025 \times 160 \times 120 = 480000
    1800×20=360001800 \times 20 = 36000
    480000/36000=480/36=40/3=13.333...480000 / 36000 = 480 / 36 = 40 / 3 = 13.333...

    It's possible the problem expects a rounded answer or there's an error in the problem statement's numbers. Given that teeth must be integers, I will provide the exact fraction and note the non-integer result. However, if this is a multiple choice question, I would look for the closest integer. Assuming it expects an exact calculation:

    TY=403 teethT_Y = \frac{40}{3} \text{ teeth}

    The number of teeth of gear Y is 13.33\boxed{\text{13.33}}.

    1.3 Name the measuring equipment used to measure each of the following in electrical circuits:

    1.3.1 Potential difference
    A voltmeter is used to measure potential difference.

    1.3.2 Resistance
    An ohmmeter is used to measure resistance.

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