This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Haya Detroit, twende na swali la 6. Ili kutatua tatizo hili, tutatumia kanuni ya uhifadhi wa nishati, ambapo joto lililopotea na mvuke ni sawa na joto lililopatikana na maji na chombo cha kioo. Step 1: Badilisha wingi wa maji na chombo cha kioo kutoka gramu kwenda kilogramu. m_w = 200 g = 0.2 kg m_g = 100 g = 0.1 kg Step 2: Kokotoa joto lililopatikana na maji na chombo cha kioo. Maji na chombo cha kioo hupashwa moto kutoka 20^ C hadi 50^ C. T_w/g = 50^ C - 20^ C = 30^ C Joto lililopatikana na maji: Q_w = m_w c_w T_w/g = (0.2 kg) × (4200 J/KgK) × (30 K) Q_w = 25200 J Joto lililopatikana na chombo cha kioo: Q_g = m_g c_g T_w/g = (0.1 kg) × (840 J/KgK) × (30 K) Q_g = 2520 J Jumla ya joto lililopatikana: Q_iliyopatikana = Q_w + Q_g = 25200 J + 2520 J Q_iliyopatikana = 27720 J Step 3: Kokotoa joto lililopotea na mvuke katika hatua tatu. Acha m_s iwe wingi wa mvuke. a) Mvuke hupoa kutoka 130^ C hadi 100^ C: T_s1 = 130^ C - 100^ C = 30^ C Q_s1 = m_s c_s T_s1 = m_s × (200 J/KgK) × (30 K) Q_s1 = 6000 m_s J b) Mvuke hufupishwa kuwa maji kwenye 100^ C: Q_s2 = m_s L_v = m_s × (2.26 × 10^6 J/Kg) Q_s2 = 2260000 m_s J c) Maji yaliyofupishwa hupoa kutoka 100^ C hadi 50^ C: T_s3 = 100^ C - 50^ C = 50^ C Q_s3 = m_s c_w T_s3 = m_s × (4200 J/KgK) × (50 K) Q_s3 = 210000 m_s J Jumla ya joto lililopotea na mvuke: Q_iliyopotea = Q_s1 + Q_s2 + Q_s3 Q_iliyopotea = (6000 + 2260000 + 210000) m_s J Q_iliyopotea = 2476000 m_s J Step 4: Linganisha joto lililopotea na joto lililopatikana. Q_iliyopotea = Q_iliyopatikana 2476000 m_s = 27720 m_s = (27720)/(2476000) m_s ≈ 0.011195 kg Step 5: Toa jibu la mwisho. Wingi wa mvuke unahitajika ni takriban 0.0112 kg. Wingi wa mvuke = 0.0112 kg That's 2 down. 3 left today — send the next one.