We read your photo as:

Describe the nuclear reaction shown and identify the isotope with the longest half-life and calculate the relative atomic mass of uranium.

Physics

ScanSolve AI Answer

Step-by-step solution

14 steps

4. (a)
The nuclear reaction shown is:

92235U+01n⟶56139Ba+3694Kr+301n^{235}_{92}U + ^{1}_{0}n \longrightarrow ^{139}_{56}Ba + ^{94}_{36}Kr + 3^{1}_{0}n

This reaction represents a heavy nucleus (235U^{235}U) splitting into lighter nuclei (139Ba^{139}Ba and 94Kr^{94}Kr) after absorbing a neutron, releasing energy and more neutrons.
This type of nuclear reaction is nuclear fission.

4. (b) (i)
Based on the provided table:

IsotopeAbundance
238U^{238}U0.01%
235U^{235}U0.72%
234U^{234}U99.27%

The isotope with the longest half-life is 234U\boxed{^{234}U}.
Reason: It has the highest abundance (99.27%) in the given sample, which suggests it has decayed less over geological time compared to the other isotopes listed with lower abundances.

4. (b) (ii)

  1. Use the given abundances and mass numbers to calculate the relative atomic mass.

    Relative atomic mass = ∑(isotope mass×abundance)\sum (\text{isotope mass} \times \text{abundance})

    =(238×0.0001)+(235×0.0072)+(234×0.9927)= (238 \times 0.0001) + (235 \times 0.0072) + (234 \times 0.9927) =0.0238+1.692+232.3998= 0.0238 + 1.692 + 232.3998 =234.1156= 234.1156

    The relative atomic mass of uranium is 234.1156\boxed{234.1156}.

    4. (b) (iii)

  2. Write the incomplete nuclear equation for alpha decay of 92232U^{232}_{92}U to Thorium (Th).

    92232U⟶ZATh+24α^{232}_{92}U \longrightarrow ^{A}_{Z}Th + ^{4}_{2}\alpha
  3. Balance the mass numbers (superscripts).

    232=A+4  ⟹  A=232−4=228232 = A + 4 \implies A = 232 - 4 = 228
  4. Balance the atomic numbers (subscripts).

    92=Z+2  ⟹  Z=92−2=9092 = Z + 2 \implies Z = 92 - 2 = 90
  5. Write the complete nuclear equation.

    92232U⟶90228Th+24α\boxed{^{232}_{92}U \longrightarrow ^{228}_{90}Th + ^{4}_{2}\alpha}

    4. (b) (iv)
    One use of radioactive isotopes in the paper industry is to measure and control the thickness of paper\boxed{\text{measure and control the thickness of paper}}.

    5. (a)

  6. Write the incomplete nuclear equation for the decay of carbon-14 (614C^{14}_{6}C) to nitrogen (714N^{14}_{7}N).

    614C⟶714N+yxP^{14}_{6}C \longrightarrow ^{14}_{7}N + ^{x}_{y}P
  7. Balance the mass numbers (superscripts).

    14=14+x  ⟹  x=014 = 14 + x \implies x = 0
  8. Balance the atomic numbers (subscripts).

    6=7+y  ⟹  y=−16 = 7 + y \implies y = -1
  9. Identify the emitted particle.

    A particle with mass number 0 and atomic number -1 is a beta particle (−10e^{0}_{-1}e).

  10. Write the complete nuclear equation.

    614C⟶714N+−10e\boxed{^{14}_{6}C \longrightarrow ^{14}_{7}N + ^{0}_{-1}e}

    5. (b) (i)

  11. Locate 50% on the y-axis (percentage of carbon-14 left).

  12. Draw a horizontal line from 50% to intersect the decay curve.

  13. From the intersection point on the curve, draw a vertical line down to the x-axis (age of sample in years).

  14. Read the value on the x-axis.

    The value is approximately 5.7×1035.7 \times 10^3 years.
    The half-life of carbon-14 from the graph is 5.7×103 years\boxed{5.7 \times 10^3 \text{ years}}.

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp