This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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1) Ohm's law states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points, and inversely proportional to the resistance between them. V = IR where V is voltage, I is current, and R is resistance. 2) Calculate the reading of the instruments labeled A and V. Given: Supply voltage V_supply = 12 V Resistance R = 5.5 Step 1: Calculate the current (reading of ammeter A). Using Ohm's law, I = (V)/(R). I = 12 V5.5 I ≈ 2.1818 A The reading of instrument A is approximately 2.18 A. Step 2: Calculate the voltage across the resistor (reading of voltmeter V). Since the resistor is connected directly across the 12 V supply in a simple series circuit, the voltage across it is equal to the supply voltage. V_resistor = V_supply V_resistor = 12 V The reading of instrument V is 12 V. 3) What is the cost of using resistor R for 6 hours a day for 30 days if power costs 15N per kWh? Step 1: Calculate the power dissipated by the resistor. Power P = (V^2)/(R) P = (12 V)^25.5 P = 144 V^25.5 P ≈ 26.1818 W Step 2: Calculate the total time of usage in hours. Total time t = 6 hours/day × 30 days t = 180 hours Step 3: Calculate the total energy consumed in kilowatt-hours (kWh). Energy E = P × t E = 26.1818 W × 180 hours E = 4712.724 Wh Convert Watt-hours to kilowatt-hours: E = 4712.724 Wh1000 Wh/kWh E ≈ 4.7127 kWh Step 4: Calculate the total cost. Cost = Energy consumed × Cost per kWh Cost = 4.7127 kWh × 15 N/kWh Cost ≈ 70.6905 N The total cost is approximately 70.69 N. Final Answers: 1) Ohm's law: V = IR 2) Ammeter reading (A): 2.18 A Voltmeter reading (V): 12 V 3) Cost of using resistor R: 70.69 N Send me the next one 📸