Physics ka question hai solve ho jayega

August 20, 2026Physics

ScanSolve AI Answer

August 20, 2026

Answer

$9 \times 10^{16} \, \text{J}$

Step 1: $E = mc^2$ $3 \times 10^8 \, m/s$ $1 \, kg$ $E = (1 \, kg) \times (3 \times 10^8 \, m/s)^2$ $E = 1 \, kg \times 9 \times 10^{16} \, m^2/s^2$ $E = 9 \times 10^{16} \, J$

$9 \times 10^{16 \, J}$

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E = mc^2 3 × 10^8 \, m/s 1 \, kg E = (1 \, kg) × (3 × 10^8 \, m/s)^2 E = 1 \, kg × 9 × 10^16 \, m^2/s^2 E = 9 × 10^16 \, J 9 × 10^16 \, J अगला प्रश्न भेजें 📸…

Asked on August 20, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI AnswerAnswered on August 20, 2026

Step 1: E = mc^2 3 × 10^8 \, m/s 1 \, kg E = (1 \, kg) × (3 × 10^8 \, m/s)^2 E = 1 \, kg × 9 × 10^16 \, m^2/s^2 E = 9 × 10^16 \, J 9 × 10^16 \, J अगला प्रश्न भेजें 📸