They are maths question not physics
Physics
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Step-by-step solution
4 stepsHere's how to solve the quadratic equation x² + 5x + 6 = 0.
Identify the coefficients a, b, and c from the standard quadratic form ax² + bx + c = 0.
In this equation, a = 1, b = 5, and c = 6.
Use the quadratic formula
x = [-b ± √(b² - 4ac)] / (2a).
Substitute the values of a, b, and c into the formula:
x = [-5 ± √(5² - 4 × 1 × 6)] / (2 × 1)Simplify the expression under the square root (the discriminant).
x = [-5 ± √(25 - 24)] / 2
x = [-5 ± √1] / 2Calculate the two possible values for x.
x₁ = (-5 + 1) / 2 = -4 / 2 = -2
x₂ = (-5 - 1) / 2 = -6 / 2 = -3The solutions are x = -2 and x = -3.
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