Force F1 = 30 N: Applied at the left end. The diagram shows it pulling upwards and to the left, making an angle of 30^ with the horizontal.

To solve this problem, we need to apply the conditions for static equilibrium to the horizontal beam. We will assume the beam is massless and that the forces and masses are applied at the ends of the beam as depicted. Let $g = 9.8 \, \text{m/s}^2$.

Let's define the forces acting on the beam:

• Force $F_1 = 30 \, \text{N}$: Applied at the left end. The diagram shows it pulling upwards and to the left, making an angle of $30^\circ$ with the horizontal.
  • Horizontal component: $F_{1x} = -30 \cos(30^\circ)$ (to the left)
  • Vertical component: $