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Calculate the primary phase voltage (3.3.1)

Physics

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Step-by-step solution

4 steps
  1. Calculate the primary phase voltage (3.3.1)

    Given:
    Primary line voltage VL1=6.6 kV=6600 VV_{L1} = 6.6 \text{ kV} = 6600 \text{ V}
    The transformer is delta-star connected, meaning the primary side is delta-connected.
    For a delta connection, the line voltage is equal to the phase voltage.

    Vph1=VL1V_{ph1} = V_{L1} Vph1=6600 VV_{ph1} = 6600 \text{ V}

    The primary phase voltage is 6600 V\boxed{6600 \text{ V}}.

  2. Calculate the transformer ratio (3.3.2)

    Given:
    Primary phase voltage Vph1=6600 VV_{ph1} = 6600 \text{ V}
    Secondary phase voltage Vph2=240 VV_{ph2} = 240 \text{ V}
    The transformer ratio (aa) is the ratio of primary phase voltage to secondary phase voltage:

    a=Vph1Vph2a = \frac{V_{ph1}}{V_{ph2}} a=6600 V240 Va = \frac{6600 \text{ V}}{240 \text{ V}} a=27.5a = 27.5

    The transformer ratio is 27.5\boxed{27.5}.

  3. Calculate the secondary line voltage (3.3.3)

    Given:
    Secondary phase voltage Vph2=240 VV_{ph2} = 240 \text{ V}
    The transformer is delta-star connected, meaning the secondary side is star-connected.
    For a star connection, the line voltage is 3\sqrt{3} times the phase voltage:

    VL2=3×Vph2V_{L2} = \sqrt{3} \times V_{ph2} VL2=3×240 VV_{L2} = \sqrt{3} \times 240 \text{ V} VL2≈1.732×240 VV_{L2} \approx 1.732 \times 240 \text{ V} VL2≈415.68 VV_{L2} \approx 415.68 \text{ V}

    The secondary line voltage is 415.68 V\boxed{415.68 \text{ V}}.

  4. Calculate the rating of a transformer (3.3.4)

    The rating of a transformer is typically expressed in kVA (kilovolt-amperes). To calculate the rating, the current (either line or phase) on either the primary or secondary side is required. Since no current information is provided in the question, the transformer rating cannot be determined.

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