When a pure semiconductor is heated, its resistance decreases.

Question

When a pure semiconductor is heated, its resistance decreases.

Asked on March 27, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

Accepted Answer · 2026-03-27T17:38:16.479Z

When a pure semiconductor is heated, its resistance decreases. This is because heating a semiconductor provides thermal energy to its electrons, allowing more electrons to break free from their covalent bonds and move into the conduction band. This increases the number of free charge carriers (electrons and holes), which in turn increases the material's electrical conductivity and thus decreases its resistance. The final answer is $\boxed{\text{B. decreases}}$.

Accepted Answer · 2026-03-27T17:38:16.479Z

When a pure semiconductor is heated, its resistance decreases. This is because heating a semiconductor provides thermal energy to its electrons, allowing more electrons to break free from their covalent bonds and move into the conduction band. This increases the number of free charge carriers (electrons and holes), which in turn increases the material's electrical conductivity and thus decreases its resistance. The final answer is $\boxed{\text{B. decreases}}$.