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Recall the relationships between the coefficients of thermal expansion.

Physics

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: Coefficients of Thermal Expansion

  1. Recall the relationships between the coefficients of thermal expansion.

    The coefficient of linear expansion is α\alpha.
    The coefficient of area expansion is β\beta.
    The coefficient of volume expansion is γ\gamma.

    These coefficients are related as follows:

    β=2α\beta = 2\alpha γ=3α\gamma = 3\alpha
  2. Check each given option against these relationships.

    • Option A: α=2β\alpha = 2\beta Substitute β=2α\beta = 2\alpha: α=2(2α)  ⟹  α=4α\alpha = 2(2\alpha) \implies \alpha = 4\alpha. This is incorrect.

    • Option B: γ=2β3\gamma = \frac{2\beta}{3} Substitute β=2α\beta = 2\alpha and γ=3α\gamma = 3\alpha: 3α=2(2α)33\alpha = \frac{2(2\alpha)}{3} 3α=4α33\alpha = \frac{4\alpha}{3}. This is incorrect. Alternatively, from β=2α\beta = 2\alpha and γ=3α\gamma = 3\alpha, we can derive γ=32β\gamma = \frac{3}{2}\beta. So, 2β3\frac{2\beta}{3} is incorrect.

    • Option C: β=3γ2\beta = \frac{3\gamma}{2} Substitute β=2α\beta = 2\alpha and γ=3α\gamma = 3\alpha: 2α=3(3α)22\alpha = \frac{3(3\alpha)}{2} 2α=9α22\alpha = \frac{9\alpha}{2}. This is incorrect. Alternatively, from β=2α\beta = 2\alpha and γ=3α\gamma = 3\alpha, we can derive β=23γ\beta = \frac{2}{3}\gamma. So, 3γ2\frac{3\gamma}{2} is incorrect.

    Since none of the first three options are correct, the correct choice is "None of the other options".

    The correct option is None of the other options\boxed{\text{None of the other options}}.


    : Adiabatic Expansion of an Ideal Monatomic Gas

  3. Understand the characteristics of an adiabatic expansion.

    An adiabatic process means no heat exchange with the surroundings (Q=0Q = 0).
    An expansion means the volume of the gas increases, and the gas does work on its surroundings (W>0W > 0).

  4. Apply the First Law of Thermodynamics.

    The First Law of Thermodynamics states ΔU=Q−W\Delta U = Q - W.
    Since Q=0Q = 0 for an adiabatic process, the equation becomes ΔU=−W\Delta U = -W.
    Since it's an expansion, W>0W > 0. Therefore, ΔU=−(positive value)\Delta U = -(\text{positive value}), which means ΔU<0\Delta U < 0.
    A decrease in internal energy (ΔU<0\Delta U < 0) for an ideal gas implies a decrease in its temperature (TT).

  5. Analyze the statements based on the temperature change.

    • I. The work done is zero. In an expansion (not free expansion), the gas does work against external pressure, so W>0W > 0. This statement is incorrect.

    • II. The average speed of the atoms increases. Since the temperature decreases, the average kinetic energy of the atoms decreases. The average speed of the atoms is directly related to their average kinetic energy, so the average speed must decrease. This statement is incorrect.

    • III. The average speed of the atoms remains constant. As explained above, the temperature decreases, so the average speed of the atoms decreases. This statement is incorrect.

    • IV. The average speed of the atoms decrease. As the temperature of the gas decreases during an adiabatic expansion, the average kinetic energy of its atoms decreases, which in turn means their average speed decreases. This statement is correct.

  6. Select the correct option.

    Only statement IV is correct.

    The correct option is IV only\boxed{\text{IV only}}.

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