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Explain the terms: principal axis, optical centre, and principal focus of a converging lens. Also, calculate the image distance and magnification for an object placed 15 cm away from a converging lens

Physics

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b(ii)

30 cm30 \text{ cm}

b(iii)
2

here are the solutions to question 7:

  1. a) i) The principal axis is an imaginary straight line passing through the optical centre of the lens and perpendicular to its surfaces. ii) The optical centre is the central point of a lens through which light rays pass without undergoing any deviation. iii) The principal focus (or focal point) of a converging lens is the point on the principal axis where parallel rays of light, after passing through the lens, converge.

    b) Given:
    Object distance, u=15 cmu = 15 \text{ cm}
    Focal length of converging lens, f=10 cmf = 10 \text{ cm}

    i) Since the object is placed between ff (10 cm10 \text{ cm}) and 2f2f (20 cm20 \text{ cm}) for a converging lens, the image formed is real, inverted, and magnified.

    ii) To calculate the image distance (vv), use the lens formula:

    1f=1u+1v\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

    Rearrange to solve for vv:

    1v=1f−1u\frac{1}{v} = \frac{1}{f} - \frac{1}{u}

    Substitute the given values:

    1v=110 cm−115 cm\frac{1}{v} = \frac{1}{10 \text{ cm}} - \frac{1}{15 \text{ cm}}

    Find a common denominator:

    1v=330 cm−230 cm\frac{1}{v} = \frac{3}{30 \text{ cm}} - \frac{2}{30 \text{ cm}} 1v=130 cm\frac{1}{v} = \frac{1}{30 \text{ cm}} v=30 cmv = 30 \text{ cm}

    The image distance is 30 cm\boxed{30 \text{ cm}}.

    iii) To calculate the magnification (MM), use the formula:

    M=vuM = \frac{v}{u}

    Substitute the values:

    M=30 cm15 cmM = \frac{30 \text{ cm}}{15 \text{ cm}} M=2M = 2

    The magnification is 2\boxed{2}.

    c) Two differences between the eye and a camera are:

    • The eye focuses by changing the focal length of its lens (accommodation), while a camera focuses by changing the distance between its lens and the film/sensor.
    • The eye uses a retina as its light-sensitive part, whereas a camera uses photographic film or a digital sensor (CCD/CMOS).

    d) Two applications of total internal reflection are:

    • Optical fibers: Used for high-speed data transmission and in medical endoscopes.
    • Periscopes and binoculars: Use prisms to reflect light, allowing for compact designs and brighter images.
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