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Show that the impulse reduces the speed of the particle but does not reverse its direction.

Physics

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*a) Show that the impulse reduces the speed of the particle but does not reverse its direction.
Let the initial velocity be vi=4uv_i = 4u. The mass of the particle is mp=2mm_p = 2m.
The impulse I=3muI = 3mu is directed opposite to the initial motion. If we take the initial direction as positive, the impulse is −3mu-3mu.
Using the impulse-momentum theorem: I=Δp=mpvf−mpviI = \Delta p = m_p v_f - m_p v_i.

−3mu=(2m)vf−(2m)(4u)-3mu = (2m)v_f - (2m)(4u)
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