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The diagram shows a ship moving towards a cliff. The sound from the siren of the reflected by the cliff and heard 6.0s later by the sailor on the ship. How far from the cliff is the ship, taking the speed of sound in air to be 330m/s?

Physics

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Answer

B

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Here are the solutions to the problems:

A7: Absolute Zero

  1. Analyze each statement regarding absolute zero.

    • A: "equal to zero Kelvin on the absolute temperature scale." This is the definition of absolute zero, so it is true.
    • B: "equivalent to 273∘C273^\circ \text{C} on the absolute temperature scale." Absolute zero is 0 K0 \text{ K}, which is equivalent to −273.15∘C-273.15^\circ \text{C}. Therefore, 273∘C273^\circ \text{C} is not absolute zero; this statement is not true.
    • C: "represented by ∘C^\circ \text{C}." Absolute zero is represented as 0 K0 \text{ K} on the absolute temperature scale. While it can be expressed in Celsius, its representation on the absolute scale is Kelvin. So, this statement is also not true.
    • D: "the lowest possible temperature at which the volume of a gas is assumed to be zero." This is a consequence of the ideal gas law and is considered true in the context of ideal gases.
  2. Identify the statement that is not true.

    Both B and C are not true. However, statement B presents a direct numerical inaccuracy (273∘C273^\circ \text{C} instead of −273∘C-273^\circ \text{C}), which is a fundamental error in the value of absolute zero in Celsius. Statement C is about the unit of representation, which is Kelvin for the absolute scale. In physics, the conversion error in B is typically considered the more significant "not true" statement in such questions.

    The correct option is B.

    B\boxed{\text{B}}

    A8: Wave Travel Time

  3. Calculate the speed of the waves.

    Given frequency f=500 Hzf = 500 \text{ Hz} and wavelength λ=0.05 m\lambda = 0.05 \text{ m}.
    The wave speed vv is given by the formula:

    v=fλv = f \lambda v=500 Hz×0.05 m=25 m/sv = 500 \text{ Hz} \times 0.05 \text{ m} = 25 \text{ m/s}
  4. Calculate the time taken for the waves to travel the given distance.

    Given distance d=1250 md = 1250 \text{ m}.
    The time tt is given by the formula:

    t=dvt = \frac{d}{v} t=1250 m25 m/s=50 st = \frac{1250 \text{ m}}{25 \text{ m/s}} = 50 \text{ s}

    The correct option is C.

    C\boxed{\text{C}}

    A9: Frequency of Red Light

  5. Identify the given values and constants.

    Wavelength of red light λ=7.5×10−7 m\lambda = 7.5 \times 10^{-7} \text{ m}.
    The speed of light (an electromagnetic wave) in a vacuum or air is approximately c=3.0×108 m/sc = 3.0 \times 10^8 \text{ m/s}.

  6. Use the wave equation to calculate the frequency.

    The relationship between speed of light (cc), frequency (ff), and wavelength (λ\lambda) is:

    c=fλc = f \lambda

    Rearranging for frequency:

    f=cλf = \frac{c}{\lambda}
  7. Substitute the values and calculate the frequency.

    f=3.0×108 m/s7.5×10−7 mf = \frac{3.0 \times 10^8 \text{ m/s}}{7.5 \times 10^{-7} \text{ m}} f=3.07.5×108−(−7) Hzf = \frac{3.0}{7.5} \times 10^{8 - (-7)} \text{ Hz} f=0.4×1015 Hzf = 0.4 \times 10^{15} \text{ Hz} f=4.0×1014 Hzf = 4.0 \times 10^{14} \text{ Hz}

    The correct option is B.

    B\boxed{\text{B}}

    A10: Distance from Cliff (Echo)

  8. Determine the total distance traveled by the sound.

    The sound travels from the ship to the cliff and then reflects back to the ship. The total time taken for this round trip is 6.0 s6.0 \text{ s}.
    Given the speed of sound v=330 m/sv = 330 \text{ m/s}.
    Total distance dtotald_{\text{total}} is:

    dtotal=v×td_{\text{total}} = v \times t dtotal=330 m/s×6.0 s=1980 md_{\text{total}} = 330 \text{ m/s} \times 6.0 \text{ s} = 1980 \text{ m}
  9. Calculate the distance from the ship to the cliff.

    The distance from the ship to the cliff is half of the total distance traveled by the sound, as the sound makes a round trip.

    dship-cliff=dtotal2d_{\text{ship-cliff}} = \frac{d_{\text{total}}}{2} dship-cliff=1980 m2=990 md_{\text{ship-cliff}} = \frac{1980 \text{ m}}{2} = 990 \text{ m}

    The correct option is C.

    C\boxed{\text{C}}
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