What is the power required to lift a 340n weight to a height of 3.5 meters in 5s

Physics

ScanSolve AI Answer

Answer

238 W238\ \text{W}

Step-by-step solution

2 steps

The power required to lift the weight is 238 W.

  1. Calculate the Work Done

    Work (W) is defined as the force applied over a distance.
    W=F×dW = F \times d
    Where:
    F=340 NF = 340\ \text{N} (force/weight)
    d=3.5 md = 3.5\ \text{m} (distance/height)

    W=340 N×3.5 mW = 340\ \text{N} \times 3.5\ \text{m}
    W=1190 JW = 1190\ \text{J}

  2. Calculate the Power Required

    Power (P) is the rate at which work is done, or work divided by time.
    P=WtP = \frac{W}{t}
    Where:
    W=1190 JW = 1190\ \text{J} (work done)
    t=5 st = 5\ \text{s} (time taken)

    P=1190 J5 sP = \frac{1190\ \text{J}}{5\ \text{s}}
    P=238 WP = 238\ \text{W}

    The power required is 238\ W.

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