This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Hapa kuna majibu ya maswali yako: 1. Which of the following is a warming process b) condensation Condensation ni mchakato wa kupoza ambapo gesi hubadilika kuwa kioevu na kutoa joto la siri kwa mazingira, na hivyo kuyapasha joto. Uvukizi ni mchakato wa kupoza. Kuchemka kunahitaji joto kuendelea, lakini hakutoi joto kwa mazingira. 2. Melting is a process in which solid phase changes to b) liquid phase at constant temperature Kuyeyuka ni mabadiliko kutoka hali imara kwenda hali ya kioevu. Wakati wa kuyeyuka, joto la dutu hubaki mara kwa mara kwani joto la siri la kuyeyuka hufyonzwa. 3. Three bodies A, B and C are in thermal equilibrium. The temperature of B is 45°C. The temperature of C is a) 45°C Ikiwa miili mitatu (A, B, na C) iko katika usawa wa joto, inamaanisha kuwa yote yana joto sawa. Kwa hivyo, ikiwa joto la B ni 45^ C, basi joto la C pia ni 45^ C. 4. The temperature of a steel rod is 330K. Its temperature in °C is b) 57°C Ili kubadilisha joto kutoka Kelvin kwenda Selsiasi, tunatumia fomula: T(^ C) = T(K) - 273 T(^ C) = 330 - 273 T(^ C) = 57^ C 5. When ice melts, its temperature a) remains constant Wakati barafu inayeyuka, joto lake hubaki mara kwa mara (0^ C) hadi barafu yote imeyeyuka na kuwa maji. Joto linalofyonzwa hutumika kubadilisha hali (joto la siri la kuyeyuka) badala ya kuongeza joto. 3 done, 2 left today. You're making progress.