This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here are the solutions to the questions: a) The velocity ratio (VR) of a machine is defined as the ratio of the distance moved by the effort to the distance moved by the load. Velocity Ratio = Distance moved by effortDistance moved by load b) Given: Mass of load, m = 20 \, kg Effort force, F = 150 \, N Vertical height, h = 3 \, m Length of inclined plane (distance moved by effort), L = 5 \, m Acceleration due to gravity, g = 10 \, m/s^2 (assumed) i) The work done on the load Step 1: Calculate the weight of the load. The weight of the load is the force of gravity acting on it. Weight = m × g Weight = 20 \, kg × 10 \, m/s^2 Weight = 200 \, N Step 2: Calculate the work done on the load. Work done on the load is the product of its weight and the vertical height it is lifted. W_load = Weight × h W_load = 200 \, N × 3 \, m W_load = 600 \, J The work done on the load is 600 J. ii) Work done by the effort Step 1: Identify the effort force and the distance moved by the effort. Effort force, F = 150 \, N Distance moved by effort (length of the inclined plane), L = 5 \, m Step 2: Calculate the work done by the effort. Work done by the effort is the product of the effort force and the distance it moves. W_effort = F × L W_effort = 150 \, N × 5 \, m W_effort = 750 \, J The work done by the effort is 750 J.