This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Here are the solutions to the questions: Three charges are arranged as shown in Fig below Find the force on the charge Q3 assuming that, Q1 is -9.0 10^-6 C, Q2 is 3 10^-6 C and Q3 is -6 * 10^-6 C when Q1 and Q3 are 2.0 m from Q2. /3 marks Given: Q_1 = -9.0 × 10^-6 C Q_2 = +3.0 × 10^-6 C Q_3 = -6.0 × 10^-6 C Distance between Q_1 and Q_2, r_12 = 2.0 m Distance between Q_2 and Q_3, r_23 = 2.0 m Distance between Q_1 and Q_3, r_13 = r_12 + r_23 = 2.0 m + 2.0 m = 4.0 m Coulomb's constant, k = 8.99 × 10^9 N m^2 C^-2 Step 1: Calculate the force F_13 exerted by Q_1 on Q_3. Since Q_1 and Q_3 are both negative, they repel each other. The force F_13 on Q_3 is directed to the right. F_13 = k (|Q_1 Q_3|)/(r_13)^2 F_13 = (8.99 × 10^9 N m^2 C^-2) |(-9.0 × 10^-6 C)(-6.0 × 10^-6 C)|(4.0 m)^2 F_13 = (8.99 × 10^9) 54.0 × 10^-1216.0 F_13 = 0.03034125 N Step 2: Calculate the force F_23 exerted by Q_2 on Q_3. Since Q_2 is positive and Q_3 is negative, they attract each other. The force F_23 on Q_3 is directed to the left. F_23 = k (|Q_2 Q_3|)/(r_23)^2 F_23 = (8.99 × 10^9 N m^2 C^-2) |(3.0 × 10^-6 C)(-6.0 × 10^-6 C)|(2.0 m)^2 F_23 = (8.99 × 10^9) 18.0 × 10^-124.0 F_23 = 0.040455 N Step 3: Calculate the net force on Q_3. Let the direction to the right be positive. F_net = F_13 - F_23 F_net = 0.03034125 N - 0.040455 N F_net = -0.01011375 N The negative sign indicates the net force is directed to the left. The net force on Q_3 is 0.010 N to the left. physical properties that affect resistance of a metal wire. /3 marks The physical properties that affect the resistance of a metal wire are: • The length of the wire: Resistance is directly proportional to length. • The cross-sectional area of the wire: Resistance is inversely proportional to the cross-sectional area. • The type of material (resistivity): Different materials have different inherent resistivities. • The temperature of the wire: For most metals, resistance increases with temperature. graph of current against p.d for the following; /1 mark • For a resistor, the graph of current (I) against potential difference (p.d or V) is a straight line passing through the origin, indicating a constant resistance (Ohm's Law). • For a diode, the graph is non-linear. It shows very little current flow in reverse bias, and in forward bias, current only starts to flow significantly after a certain threshold voltage (cut-in voltage) is reached, then increases exponentially. e.m.f 3.0 V and negligible internal resistance is connected across three re... as shown in figure This question is incomplete as the full text and the accompanying figure are not visible. That's 2 down. 3 left today — send the next one.