This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Hey bilgate, good to see you again. Here are the solutions for the questions from the image: 1. (a) The type of force that exists between the two magnets shown in Figure 4 is attraction. 1. (b) Two factors that affect the size of the force between the magnets are: • The strength of the magnetic poles. • The distance between the magnetic poles. 1. (c) (Drawing the magnetic field pattern between the two magnets) You should draw magnetic field lines originating from the North pole (N) of one magnet and terminating at the South pole (S) of the other magnet. The lines should be curved, denser near the poles, and not cross each other. The pattern should clearly show the lines connecting the N pole to the S pole, indicating attraction. 1. (d) Figure 4 shows a transformer used to operate a radio set. Given: Primary voltage (V_p) = 240 V Primary turns (N_p) = 1000 turns Secondary turns (N_s) = 100 turns Secondary current (I_s) = 2 A Efficiency = 100% (i) Calculate the output voltage (V_s). Step 1: Use the transformer equation relating voltage and turns. (V_p)/(V_s) = (N_p)/(N_s) Step 2: Substitute the given values. 240 VV_s = (1000)/(100) Step 3: Solve for V_s. V_s = 240 V × (100)/(1000) V_s = 240 V × (1)/(10) V_s = 24 V The output voltage is 24 V. (ii) Calculate the current in the primary coil (I_p). Since the efficiency of the transformer is 100%, the input power equals the output power (P_p = P_s). V_p I_p = V_s I_s Step 1: Rearrange the formula to solve for I_p. I_p = (V_s I_s)/(V_p) Step 2: Substitute the known values. I_p = 24 V × 2 A240 V Step 3: Calculate the primary current. I_p = 48 W240 V I_p = 0.2 A The current in the primary coil is 0.2 A. (iii) Calculate the power of the radio set (P_s). The power of the radio set is the output power of the transformer. P_s = V_s I_s Step 1: Substitute the values for secondary voltage and current. P_s = 24 V × 2 A Step 2: Calculate the power. P_s = 48 W The power of the radio set is 48 W. (iv) State two sources of energy losses in a transformer. • Eddy current losses in the core. • Hysteresis losses in the core. • Copper losses (resistance of the windings). • Magnetic flux leakage. 5. Figure 5 shows a solenoid XY with a current flowing in the direction indicated. (i) Copy the diagram and indicate the magnetic flux pattern around the solenoid. (Drawing the magnetic flux pattern) Using the right-hand grip rule: If you curl the fingers of your right hand in the direction of the current (which goes over the top of the solenoid from right to left), your thumb points to the left. This indicates that end X is the North pole and end Y is the South pole. Draw magnetic field lines emerging from end X (North pole) and entering end Y (South pole) outside the solenoid. Inside the solenoid, the field lines should be straight and parallel, directed from Y to X. (ii) State the polarity of the ends X and Y of the solenoid. • End X is the North pole. • End Y is the South pole. Send me the next one 📸