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Use dimensional analysis to check the correctness of the following formula: v 2 = u 2 + 2as where u and v are velocities, a is acceleration and s is distance. E = mc 2 where E is energy, m is mass and c is the velocity of light. T = 2 where T is period.

Physics

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3 parts
a

Fomula ni sahihi\text{Fomula ni sahihi}

b

Fomula ni sahihi\text{Fomula ni sahihi}

c

Fomula si sahihi\text{Fomula si sahihi}

Step-by-step solution

8 steps

Haya, tutatumia uchambuzi wa vipimo (dimensional analysis) kuangalia usahihi wa fomula hizi.

Part a· 3 steps

v2=u2+2asv^2 = u^2 + 2as ambapo uu na vv ni kasi, aa ni mchapuko, na ss ni umbali.

  1. Pata vipimo vya kila kigezo.

    • Vipimo vya kasi (vv au uu): [LT−1][L T^{-1}]
    • Vipimo vya mchapuko (aa): [LT−2][L T^{-2}]
    • Vipimo vya umbali (ss): [L][L]
  2. Pata vipimo vya kila neno katika fomula.

    • Vipimo vya v2v^2:
    [v2]=([LT−1])2=[L2T−2][v^2] = ([L T^{-1}])^2 = [L^2 T^{-2}]
    • Vipimo vya u2u^2:
    [u2]=([LT−1])2=[L2T−2][u^2] = ([L T^{-1}])^2 = [L^2 T^{-2}]
    • Vipimo vya 2as2as: (Namba 2 haina vipimo)
    [2as]=[a][s]=[LT−2][L]=[L2T−2][2as] = [a][s] = [L T^{-2}][L] = [L^2 T^{-2}]
  3. Linganisha vipimo vya maneno yote.

    Kwa kuwa vipimo vya kila neno ([L2T−2][L^2 T^{-2}]) ni sawa, fomula hii ni sahihi kwa mujibu wa uchambuzi wa vipimo.

    Fomula ni sahihi\boxed{\text{Fomula ni sahihi}}

Part b

Fomula ni sahihi\text{Fomula ni sahihi}

E=mc2E = mc^2 ambapo EE ni nishati, mm ni masi, na cc ni kasi ya mwanga.

  1. Pata vipimo vya kila kigezo.

    • Vipimo vya nishati (EE): Nishati ina vipimo sawa na kazi (force ×\times distance) au kinetic energy (12mv2\frac{1}{2}mv^2).
    [E]=[M][LT−1]2=[ML2T−2][E] = [M][L T^{-1}]^2 = [M L^2 T^{-2}]
    • Vipimo vya masi (mm): [M][M]
    • Vipimo vya kasi ya mwanga (cc): [LT−1][L T^{-1}]
  2. Pata vipimo vya upande wa kulia wa fomula.

    • Vipimo vya mc2mc^2:
    [mc2]=[m][c]2=[M]([LT−1])2=[ML2T−2][mc^2] = [m][c]^2 = [M]([L T^{-1}])^2 = [M L^2 T^{-2}]
  3. Linganisha vipimo vya pande zote mbili.

    Kwa kuwa vipimo vya upande wa kushoto ([ML2T−2][M L^2 T^{-2}]) ni sawa na vipimo vya upande wa kulia ([ML2T−2][M L^2 T^{-2}]), fomula hii ni sahihi kwa mujibu wa uchambuzi wa vipimo.

    Fomula ni sahihi\boxed{\text{Fomula ni sahihi}}

Part c

Fomula si sahihi\text{Fomula si sahihi}

T=2πT = 2\pi ambapo TT ni kipindi.

  1. Pata vipimo vya kila kigezo.

    • Vipimo vya kipindi (TT): [T][T]
    • 2π2\pi ni namba isiyo na vipimo (dimensionless constant).
  2. Linganisha vipimo vya pande zote mbili.

    Upande wa kushoto una vipimo vya muda ([T][T]), lakini upande wa kulia hauna vipimo. Hii inamaanisha pande hizo mbili hazilingani kimipimo.

    Fomula si sahihi\boxed{\text{Fomula si sahihi}}
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