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Use the information below to plot a graph of extension (cm) against load (N).

Physics

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Step-by-step solution

4 steps
  1. Verify the extension values.

    The extension is calculated by subtracting the original length of the spring (at 0 N load) from the length of the spring at each load. The original length is 10.5 cm10.5 \text{ cm}.

    • For 0 N0 \text{ N}: 10.5 cm−10.5 cm=0 cm10.5 \text{ cm} - 10.5 \text{ cm} = 0 \text{ cm}
    • For 1 N1 \text{ N}: 12.5 cm−10.5 cm=2.0 cm12.5 \text{ cm} - 10.5 \text{ cm} = 2.0 \text{ cm}
    • For 2 N2 \text{ N}: 15.0 cm−10.5 cm=4.5 cm15.0 \text{ cm} - 10.5 \text{ cm} = 4.5 \text{ cm}
    • For 3 N3 \text{ N}: 17.5 cm−10.5 cm=7.0 cm17.5 \text{ cm} - 10.5 \text{ cm} = 7.0 \text{ cm}
    • For 4 N4 \text{ N}: 19.5 cm−10.5 cm=9.0 cm19.5 \text{ cm} - 10.5 \text{ cm} = 9.0 \text{ cm}
    • For 5 N5 \text{ N}: 21.5 cm−10.5 cm=11.0 cm21.5 \text{ cm} - 10.5 \text{ cm} = 11.0 \text{ cm}

    The extension value for 5 N5 \text{ N} load in your table is 11.5 cm11.5 \text{ cm}, which should be 11.0 cm11.0 \text{ cm}.

  2. Identify the variables for the axes.

    The task is to plot a graph of extension (cm) against load (N).

    • The load (N) is the independent variable and should be plotted on the x-axis.
    • The extension (cm) is the dependent variable and should be plotted on the y-axis.
  3. List the data points to be plotted.

    Using the corrected extension value for 5 N5 \text{ N}, the points to plot are (Load, Extension):

    • (0 N,0 cm)(0 \text{ N}, 0 \text{ cm})
    • (1 N,2.0 cm)(1 \text{ N}, 2.0 \text{ cm})
    • (2 N,4.5 cm)(2 \text{ N}, 4.5 \text{ cm})
    • (3 N,7.0 cm)(3 \text{ N}, 7.0 \text{ cm})
    • (4 N,9.0 cm)(4 \text{ N}, 9.0 \text{ cm})
    • (5 N,11.0 cm)(5 \text{ N}, 11.0 \text{ cm})
  4. Plot the graph.

    1. Draw two perpendicular axes. Label the horizontal axis "Load (N)" and the vertical axis "Extension (cm)".
    2. Choose appropriate scales for both axes. The x-axis should go from 0 N to at least 5 N, and the y-axis should go from 0 cm to at least 11.0 cm.
    3. Plot each data point from Step 3 on the graph.
    4. Draw a line of best fit through the plotted points. This line should be a straight line passing through the origin, as expected for a spring obeying Hooke's Law within its elastic limit.

    The corrected data for plotting is:

    Load (N)Extension (cm)0012.024.537.049.0511.0\boxed{\begin{array}{|c|c|} \hline \text{Load (N)} & \text{Extension (cm)} \\ \hline 0 & 0 \\ 1 & 2.0 \\ 2 & 4.5 \\ 3 & 7.0 \\ 4 & 9.0 \\ 5 & 11.0 \\ \hline \end{array}}
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