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For which of the reactions is the net ionic equation: H^+ + OH^- -> H₂O?

Chemistry

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Answer

C

4

Here are the solutions to questions 23 through 29:

  1. For which of the reactions is the net ionic equation: H++OH−→H2OH^+ + OH^- \rightarrow H_2O? This net ionic equation represents the neutralization of a strong acid by a strong soluble base.

    • (1) CH3COOH+NaOH→CH_3COOH + NaOH \rightarrow (Weak acid + Strong base) - Net ionic equation: CH3COOH(aq)+OH−(aq)→CH3COO−(aq)+H2O(l)CH_3COOH(aq) + OH^-(aq) \rightarrow CH_3COO^-(aq) + H_2O(l).
    • (2) HNO3+Mg(OH)2→HNO_3 + Mg(OH)_2 \rightarrow (Strong acid + Insoluble/sparingly soluble strong base) - Net ionic equation: 2H+(aq)+Mg(OH)2(s)→Mg2+(aq)+2H2O(l)2H^+(aq) + Mg(OH)_2(s) \rightarrow Mg^{2+}(aq) + 2H_2O(l).
    • (3) H3PO4+Ba(OH)2→H_3PO_4 + Ba(OH)_2 \rightarrow (Weak acid + Strong base) - Net ionic equation involves H3PO4H_3PO_4 and OH−OH^-.
    • (4) HCl+KOH→HCl + KOH \rightarrow (Strong acid + Strong soluble base) - Net ionic equation: H+(aq)+OH−(aq)→H2O(l)H^+(aq) + OH^-(aq) \rightarrow H_2O(l).
    • (5) H2CO3+LiOH→H_2CO_3 + LiOH \rightarrow (Weak acid + Strong base) - Net ionic equation involves H2CO3H_2CO_3 and OH−OH^-.

    Only reaction (4) involves a strong acid and a strong soluble base that fully dissociates, resulting in the net ionic equation H++OH−→H2OH^+ + OH^- \rightarrow H_2O.

    The correct answer is C. 4.

  2. Which one of the following represents the net ionic equation for the reaction of nitric acid with aluminum hydroxide?

    • Step 1: Write the balanced molecular equation. Nitric acid (HNO3HNO_3) is a strong acid. Aluminum hydroxide (Al(OH)3Al(OH)_3) is an insoluble base. 3HNO3(aq)+Al(OH)3(s)→Al(NO3)3(aq)+3H2O(l)3HNO_3(aq) + Al(OH)_3(s) \rightarrow Al(NO_3)_3(aq) + 3H_2O(l)
    • Step 2: Write the complete ionic equation. Strong acids and soluble ionic compounds are written as dissociated ions. Insoluble compounds remain as solids. 3H+(aq)+3NO3−(aq)+Al(OH)3(s)→Al3+(aq)+3NO3−(aq)+3H2O(l)3H^+(aq) + 3NO_3^-(aq) + Al(OH)_3(s) \rightarrow Al^{3+}(aq) + 3NO_3^-(aq) + 3H_2O(l)
    • Step 3: Identify and cancel spectator ions. The spectator ion is NO3−NO_3^-. 3H+(aq)+Al(OH)3(s)→Al3+(aq)+3H2O(l)3H^+(aq) + Al(OH)_3(s) \rightarrow Al^{3+}(aq) + 3H_2O(l)

    The correct answer is A. 3H++Al(OH)3→Al3++3H2O3H^+ + Al(OH)_3 \rightarrow Al^{3+} + 3H_2O.

  3. Which one of the following is an amphoteric metal hydroxide? An amphoteric substance can react as both an acid and a base.

    • A. KOHKOH (Potassium hydroxide) is a strong base.
    • B. Ba(OH)2Ba(OH)_2 (Barium hydroxide) is a strong base.
    • C. Pb(OH)2Pb(OH)_2 (Lead(II) hydroxide) is known to be amphoteric, reacting with strong acids and strong bases.
    • D. LiOHLiOH (Lithium hydroxide) is a strong base.

    The correct answer is C. Pb(OH)2Pb(OH)_2.

  4. According to the Lewis theory, a base ______.

    • A. is a proton acceptor. (Bronsted-Lowry base)
    • B. is a proton donor. (Bronsted-Lowry acid)
    • C. makes available a share in a pair of electrons. (This is the definition of a Lewis base, an electron-pair donor.)
    • D
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