A 0.244 g sample of calcium carbonate, CaCO3 was recovered from a sample of hard water. How many formula units of CaCO3 were in the sample?
Chemistry
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Answer
There are 1.47 x 10^21 formula units of CaCO3 in the sample.
Here's how to calculate it:
1. Calculate the molar mass of CaCO3:
- Ca: 40.08 g/mol
- C: 12.01 g/mol
- O: 3 * 16.00 g/mol = 48.00 g/mol
- Molar mass of CaCO3 = 40.08 + 12.01 + 48.00 = 100.09 g/mol
2. Convert the mass of CaCO3 to moles:
- Moles = Mass / Molar mass
- Moles = 0.244 g / 100.09 g/mol = 0.0024378 mol
3. Convert moles to formula units using Avogadro's number (6.022 x 10^23 formula units/mol):
- Formula units = Moles * Avogadro's number
- Formula units = 0.0024378 mol * 6.022 x 10^23 formula units/mol
- Formula units = 1.46746 x 10^21 formula units
4. Round to the appropriate number of significant figures (3, based on 0.244 g):
- Formula units = 1.47 x 10^21 formula units
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