This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
There are 1.47 x 10^21 formula units of CaCO3 in the sample. Here's how to calculate it: 1. Calculate the molar mass of CaCO3: Ca: 40.08 g/mol C: 12.01 g/mol O: 3 16.00 g/mol = 48.00 g/mol Molar mass of CaCO3 = 40.08 + 12.01 + 48.00 = 100.09 g/mol 2. Convert the mass of CaCO3 to moles: Moles = Mass / Molar mass Moles = 0.244 g / 100.09 g/mol = 0.0024378 mol 3. Convert moles to formula units using Avogadro's number (6.022 x 10^23 formula units/mol): Formula units = Moles Avogadro's number Formula units = 0.0024378 mol 6.022 x 10^23 formula units/mol Formula units = 1.46746 x 10^21 formula units 4. Round to the appropriate number of significant figures (3, based on 0.244 g): Formula units = 1.47 x 10^21 formula units