A container has 2 g of gas A at 1 atm. 3 g of gas B is added. The total pressure becomes 1.5 atm. What is the molar mass of gas B?

Here are the solutions to the problems:

Question 52:

Step 1: Identify the given information and the relevant gas law.
We are given:

• Initial gas A: $m_A = 2$ g, $P_A = 1$ atm.
• Added gas B: $m_B = 3$ g.
• Final total pressure: $P_{total} = 1.5$ atm.
• Temperature and volume are constant. For ideal gases at constant temperature and volume, pressure is directly proportional to the number of moles ($P \propto n$). Also, $n = \frac{m}{M}$. So, $P \propto \frac{m}{M}$.

Step