This chemistry question involves key chemical concepts and calculations. The detailed solution below walks through each step, from identifying the reaction type to computing the final answer.
ScanSolve AI Answer
Step 1: Write the balanced chemical equation for the oxidation of ethanol to ethanoic acid. Ethanol (CH_3CH_2OH) is oxidized to ethanoic acid (CH_3COOH) using an oxidizing agent like acidified potassium dichromate(VI). The balanced equation is: CH_3CH_2OH + 2[O] CH_3COOH + H_2O From the equation, 1 mole of ethanol produces 1 mole of ethanoic acid. Step 2: Calculate the moles of ethanol. The molar mass of ethanol (C_2H_5OH) is given as 46 g/mol. The mass of ethanol is 2.30 g. Moles of ethanol = MassMolar mass = 2.30 g46 g/mol = 0.050 mol Step 3: Determine the theoretical moles of ethanoic acid. Since the mole ratio of ethanol to ethanoic acid is 1:1, the theoretical moles of ethanoic acid produced will be equal to the moles of ethanol. Theoretical moles of ethanoic acid = 0.050 mol Step 4: Calculate the theoretical mass of ethanoic acid. The molar mass of ethanoic acid (CH_3COOH) is given as 60 g/mol. Theoretical mass of ethanoic acid = Moles × Molar mass = 0.050 mol × 60 g/mol = 3.0 g Step 5: Calculate the actual mass of ethanoic acid collected using the given yield. The yield of the product was 60.0%. Actual mass collected = Theoretical mass × Yield100\% = 3.0 g × (60.0)/(100) = 1.8 g The mass of product collected was 1.8 g. 1.8 g Send me the next one 📸