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A student found a bottle containing CH3CH2COOCH3. a) Name the process of formation of the substance above. b) Identify the two substances from which the substance is formed.

Chemistry

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2 parts
a

Esterification\text{Esterification}

b

Propanoic acid and Methanol\text{Propanoic acid and Methanol}

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Here's the solution for the next part of your question.

A student found a bottle containing CH3CH2COOCH3\text{CH}_3\text{CH}_2\text{COOCH}_3.

Part a· 2 steps

Name the process of formation of the substance above.

  1. Identify the functional group of the substance CH3CH2COOCH3\text{CH}_3\text{CH}_2\text{COOCH}_3.

    This compound is an ester. Esters are formed from the reaction of a carboxylic acid and an alcohol.

  2. Name the process by which esters are formed.

    The reaction between a carboxylic acid and an alcohol to form an ester and water is called esterification.

    The process of formation is:

    Esterification\boxed{\text{Esterification}}

Part b

Propanoic acid and Methanol\text{Propanoic acid and Methanol}

Identify the two substances from which the substance is formed.

  1. Break down the ester CH3CH2COOCH3\text{CH}_3\text{CH}_2\text{COOCH}_3 into its acid and alcohol components.

    The CH3CH2COO\text{CH}_3\text{CH}_2\text{COO} part comes from the carboxylic acid. Adding an H\text{H} gives CH3CH2COOH\text{CH}_3\text{CH}_2\text{COOH}.
    The CH3\text{CH}_3 part comes from the alcohol. Adding an OH\text{OH} gives CH3OH\text{CH}_3\text{OH}.

  2. Name the carboxylic acid and the alcohol.

    CH3CH2COOH\text{CH}_3\text{CH}_2\text{COOH} is propanoic acid.
    CH3OH\text{CH}_3\text{OH} is methanol.

    The two substances are:

    Propanoic acid and Methanol\boxed{\text{Propanoic acid and Methanol}}
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